In the decimal number .675, the 7 holds what place value

Answers

Answer 1
Answer: To see 7's rank we can count the number of digits after ".". 7 is the second digit and given that the first digit represents the decimals, 7 will represent the hundreths.
Answer 2
Answer:

7 is representing the hundredth's place.


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Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find all solutions whenever they exist.x+3y=9
3x-y=7

Answers

\left \{ {{x+3y=9~(3)} \atop {3x-y=7(-1)}} \right. \n \n \left \{ {{3x+9y=27} \atop {-3x+y=-7}} \right. \n \n10y=20\n \ny= (20)/(10) \ny=2

x+3y=9\nx=9-3y\nx=9-3.2\nx=3

S=\{3,2\}

One solution.
x+3y=9\n 3x-y=7\ / \cdot 3\n \n x+3y=9\n 9x-3y=21\n \n 10x=30\ /:10\n x=3\n \n x+3y=9\n 3+3y=9\n 3y=6\n y=2\n one\ solution - (3;2)

The school cafeteria sells two kinds of wraps: vegetarian and chicken. The vegetarian wrap costs $1.00 and the chicken wrap costs $2.70. Today they made $119.60 from the 72 wraps sold. How many of the wraps sold were vegetarian

Answers

Answer:

vegetarians= 28

chickens= 44

Step-by-step explanation:

let the number of vegetarians be x

and chickens be y

So

x+2.7y=119.6----------1

x+y=72--------------2

from 2, x= 72-y

put x= 72-y in 1

72-y+2.7y=119.6

-y+2.7y=119.6-72

1.7y=47.6

divide both sides by 1.7

y=47.6/1.7

y=28

put y=28 in 1

x+28=72

y= 72-28

y=44

1+5=12 2+10=24 3+15=36 5+25=

Answers

5+25=48 becase you add 12 each time

Write the equation y= 5x-11 in standard form

Answers

-55 =y. I hope that helped

Whats the equation of a circle centered at (7,1) that passes through (-2,10)

Answers

The line from (7, 1) to (-2 10) is a radius of the circle.

Its length is the square root of [ (-2 - 7)² + (10 - 1)² ] =  √(81 + 81) = √162

The equation of the circle is: (x- 7)² + (y - 1)² = 162 

Can you help me, I don't understand it....

Answers


Median is the average. I'm pretty sure interquartile is the biggest number out of the two. 

Add the numbers for the first semester up, then divide by the amount of numbers. Do the same for semester two, then pick the correct answer in the multiple choices... For example in semester one you'd divide the added amount by 5.

If i'm wrong i'd like anyone to let me know what I messed up in! :)