PHYSICS HIGH SCHOOL

Salmon often jump waterfalls to reach theirbreeding grounds.
Starting 3.16 m from a waterfall 0.379 m
in height, at what minimum speed must a
salmon jumping at an angle of 37.6
◦
leave the
water to continue upstream? The acceleration
due to gravity is 9.81 m/s
2
.
Answer in units of m/s.

Answers

Answer 1
Answer:

The problem corresponds to the motion of a projectile (the salmon), with initial speed v_0, initial direction \theta=37.6^(\circ) and vertical acceleration g=9.81 m/s^2 downward. The two equations which gives the horizontal and vertical position of the salmon at time t are

S_x (t) = v_0 cos \theta t (1)

S_y (t) = v_0 sin \theta t - (1)/(2)gt^2 (2)

We can solve the problem by requiring Sx=3.16 m and Sy=0.379 m, the data of the problem.

Solving eq.(1) for t:

t=(S_x)/(v_0 cos \theta)

And substituting this expression of t into eq.(2), we get the following expression for v_0:

v_0 =\sqrt{(g S_x^2)/(2(tan \theta S_x -S_y)cos^2 \alpha)}

And substituting the numbers into the equation, we find

v_0 = 6.16 m/s

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What conditions are necessary for heat to flow?

Answers

Hey There!

A temperature difference and conductivity are the conditions for heat flow.

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A person drops a brick from the top of a building. The height of the building is 400 m and the mass of the brick is 2.00 kg. What will be the speed of the brick right before it touches the ground? Use g=10.0 m/s^2.

Answers

This question involves the conservation of energy. There are two energy in this case, potential energy and kinetic energy. Let's divid the energy into three status. 
1. Before dropping, all potential energy 
2.dropping, potential energy transformed to kinetic energy
3. before hitting the ground, all Kinetic energy.

Recall the formula for both energy, which are U=mgh, and K=1/2mv^2

Since the energy is conserved in this case ( b/c otherwise it will say in the problem), the amount of energy at the beginning should equal to the energy at the end. Therefore we have, mgh=1/2mv^2

plug the number in and solve for velocity.

2x400x10=1/2 x 2 x v^2
v^2=8000
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A silver bar 0.125 meter long is subjected to a temperature change from 200°C to 100°C. What will be the length of the bar after the temperature change? A. 0.0000189 meterB. 0.00002363 meterC. 0.124764 meterD. 0.00023635 meter

Answers

The answer is C C. 0.124764 meters. When a metal (or almost any item save water) is cooled, it shrinks, as the atoms that make it up vibrate less and less and causes the item to contract. The reverse happens when heating, as the atom vibrate faster causing it to expand. Now, even though it would shrink, the shrinkage would not be that noticeable to the naked eye, and thus, the other lengths are just FAR too short to occur.

Explanation:

ΔL =18.8 ×10 − 6 . 0.125 (100−200) =

2.35 ×10^4 m=

−0.235mm

So the bar should shrink

0.235mm

giving a new length of (changing in mm):

125−0.235= 124.7mm

Why do some people suffer for nose bleed at higher altitudes?​

Answers

Answer:because of small amount of oxygen

Explanation:

If you get higher by the atmosphere the air will start to decrease

What is the acceleration of the object?

0 m/s2
0.25 m/s2
4 m/s2
8 m/s2

Answers

The answer is 4 m/s^2.
Acceleration = Δv/Δt

Acceleration  =  (change in speed)  /  (time for the change) .

That's just the slope of the graph.

It's  4 m/s²  .

A rubber ball moving at a speed of 5 m/s hit a flat wall and returned to the thrower at 5 m/s. Which statementcorrectly describes the momentum of the rubber ball?
a. Its magnitude increased and its direction changed.
b. Its magnitude increased but its direction remained the same.
c. Its magnitude remained the same but its direction changed.
d. Its magnitude and its direction both remained the same.

Answers

The correct statement should be "Its magnitude remained the same but its direction changed". Option C is correct.

Given information:

A rubber ball moving at a speed of 5 m/s hit a flat wall and returned to the thrower at 5 m/s.

Now, the mass of the ball doesn't change and the magnitude of the velocity is also the same.

Momentum can be defined as the product of mass and velocity. It is a vector quantity because velocity is also a vector quantity, and it has magnitude and direction.

Now, the magnitude of momentum will be the same because mass and velocity don't change in magnitude.

The direction of velocity will be reversed. So, the direction of momentum will also be reversed.

Therefore, the correct statement should be "Its magnitude remained the same but its direction changed". Option C is correct.

For more details about momentum, refer to the link:

brainly.com/question/4956182

Answer:

d. Its magnitude and its direction both remained the same.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.

This ultimately implies that, the law of conservation of momentum states that if objects exert forces only on each other, their total momentum is conserved.

In this scenario, a rubber ball moving at a speed of 5 m/s hit a flat wall and returned to the thrower at 5 m/s. Thus, the statement which correctly describes the momentum of the rubber ball is that its magnitude and its direction both remained the same because its velocity didn't change while returning to the thrower.

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