I'm assuming what you mean is what can you divide 3456 by to get a natural number.
First of all every number is divisible by 1.
Every even number is divisible by 2, so since 3456 is an even number, it can be divided by 2. That would equal 1728.
2456 can also be divided by 3, to get 1782.
You can also divide it by 4, to get 865.
Divided by 6, it's 576.
Divided by 8, it's 432.
And lastly, 3456 divided by 9 is 384.
So, there isn't just one single-digit number you can divide 3456 by to get a natural number. You can divide it by 1,2,3,4,6,8, and 9.
Hope that helps!
Answer:
(a)$13
(b) Loss of $4
Step-by-step explanation:
C(q) represents Cost of producing q units.
R(q) represents Revenue generated from q units.
P(q) represents Total Profit made from producing q units.
Marginal analysis is concerned with estimating the effect on quantities such as cost, revenue, and profit when the level of production is changed by a unit amount. For example, if C(q) is the cost of producing q units of a certain commodity, then the marginal cost, MC(q), is the additional cost of producing one more unit and is given by the difference
MC(q) = C(q + 1) − C(q).
Using the estimation
C'(q)≈[TeX]\frac{C(q+1)-C(q)}{(q+1)-q}[/TeX]=C(q+1)-C(q)
We find out that MC(q)=C'(q)
We can therefore compute the marginal cost by the derivative C'(q).
This also holds for Revenue, R(q) and Profit, P(q).
(a) If C'(50)=75 and R'(50)=88
51st item.
P'(50)=R'(50)-C'(50)
=88-75=$13
The profit earned from the 51st item will be approximately $13.
(b) If C'(90)=71 and R'(90)=67, approximately how much profit is earned by the 91st item.
P'(90)=R'(90)-C'(90)
=67-71= -$4
The profit earned from the 91 st item will be approximately -$4.
There was a loss of $4.
What do I need to d
Answer: 219,185
-Multiply the place values to find the answer,
Answer:
8
Step-by-step explanation:
uh idrk all ik is that 16,000 punds = 8 tons
691 648 967 959 826 573 598 790 954
711 515 649 960 949 802 507
a. Construct the frequency distribution using classes of 500 up to 600, 600 up to 700, etc.
Texts Frequency
500 up to 600
600 up to 700
700 up to 800
800 up to 900
900 up to 1000
Total
b. Construct the relative frequency distribution, the cumulative frequency distribution and the cumulative relative frequency distribution. (Round "Relative Frequency" and "Cumulative Relative Frequency" to 2 decimal places.)
Texts Relative Frequency Cumulative Frequency Cumulative Relative Frequency
500 up to 600
600 up to 700
700 up to 800
800 up to 900
900 up to 1000
c-1. How many of the 13-year-olds sent at least 600 but less than 700 text messages?
c-1. Number of 13-year-olds
Number of 13-year-olds
c-2. How many sent less than 900 text messages?
Number of 13-year-olds
d-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? (Round your answer to the nearest whole percent.)
Percent of 13-year-olds %
d-5. What percent of the 13-year-olds sent less than 600 text messages? (Round your answer to the nearest whole percent.)
Percent of 13-year-olds %
Answer:
7 ; 19 ; 8% ; 28%
Step-by-step explanation:
Given the data:
791 542 671 672 555 582 616 961 639
691 648 967 959 826 573 598 790 954
711 515 649 960 949 802 507
How many of the 13-year-olds sent at least 600 but less than 700 text messages? = 7
c-2. How many sent less than 900 text messages? = (7 + 7 + 3 + 2) = 19
d-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? =0.08 × 100 = 8% (from relative frequency)
d-5. What percent of the 13-year-olds sent less than 600 text messages? 0.28 × 100 = 28% (from relative frequency)
By sorting text messages into classes, we can get the frequency distribution. From there, we can determine the relative and cumulative frequencies. Finally, we can examine how many students sent texts within certain ranges and express these as percentages.
To answer this question, let's first classify the amount of text messages sent by each of the 25 13-year-olds into groups or classes of 100. Then we count the frequencies, or how many text messages fall into each class. This helps us construct the frequency distribution.
The classes are: 500-600, 600-700, 700-800, 800-900, and 900-1000.
Next, we calculate the relative frequency by dividing the frequency of each class by the total number of students. We round each relative frequency to 2 decimal places.
To calculate cumulative frequency, we keep an ongoing total of frequencies as we move up the classes. The cumulative relative frequency is computed similarly but applied to the relative frequencies.
In the last part, we determine how many 13-year-olds sent at least a certain number of texts but less than another number, and convert these to percentages.
#SPJ3
Answer:
split the four extra pieces into smaller pieces to were it will give each plate the same amount.
Step-by-step explanation: