3 to the 7th power times 3 to the power of negative 4

Answers

Answer 1
Answer:
{3}^(7) * {3}^( - 4)
Multiplying to exponents is the same as adding their powers which will be equal to
{3}^(3)
Which is equal to
3 × 3 × 3
9 × 3
27

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Of the 15 students in Danielle's class, 5 went to the zoo and the rest went to the aquarium. What is the ratio of the number of students who went to the aquarium to the total number of students?
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What percent does a lender generally look for when considering the debt-to-income (DTI) ratio of a loan applicant?

Answers

a less than or equal to 36% hope i am brainliest i need it 

Answer:

a

Step-by-step explanation:

Which property of addition is shown below? a + bi + c + di = a + c + bi + di

Answers

I think the property of this addition problem is  commutative property  

The train ride at the zoo covers a distance of 2 1/2 miles in 1/3 of an hour. How many miles per hour does the train go? How far can the train travel in 3 hours? show your work.

Answers

7.5 mph in 3 hours the train can travel 22.5 miles. Take 2.5 and times it by 3 to get the mph, then multiply that answer by 3 again to get the total miles in 3 hours

A piece of wire 7/8 meter long broke into two pieces.one piece was 1/4 meter long. How is the other piece

Answers

Answer:

The second piece is 5/8 meters.

Step-by-step explanation:

To find the length of the second piece of wire, subtract the length of the first piece of wire from the total.

7/8 - 1/4

Get a common denominator:

7/8 - (1/4) *2/2

7/8 - 2/8

5/8

The second piece is 5/8 meters.

Express each number in standard form
-9.5x10-3
This is 10 to the -3 power

Answers

-9.5*10^(-3)=-9.5*0.001=-0.0095

Find the values of cosΘ and tanΘ, given that sinΘ = 8/9 and Θ is in quadrant I

Answers

sin^2 \alpha +cos^2 \alpha =1\ \ \ and\ \ \ tan \alpha = \frac{\big{sin \alpha }}{\big{cos \alpha }} \n\nsin \alpha = (8)/(9)\n\n \Rightarrow\ \ \ ((8)/(9))^2+cos^2 \alpha =1\ \ \ \Rightarrow\ \ \ cos^2 \alpha =1- (64)/(81) \ \ \ \Rightarrow\ \ \ cos^2 \alpha = (17)/(81) \n\n \alpha \ \in\ (0^0;90^0)\ \ \ \Rightarrow\ \ \ cos \alpha >0\ \ \ \Rightarrow\ \ \ cos \alpha = ( √(17) )/(9) \n\n

tan \alpha = (8)/(9): ( √(17) )/(9) =(8)/(9)\cdot (9)/(√(17))= (8)/(√(17))= (8\cdot √(17))/(√(17)\cdot √(17))=(8\cdot √(17))/(17)