The shortest wavelengths occur in the:red end of the spectrumblue end of the spectrummiddle of the spectrum The light-gathering capacity of a telescope is dependent upon the:magnificationfocal lengthsize of human irisarea of aperture

Answers

Answer 1
Answer: The shortest visible wavelength is the last color you can see
at the blue end of the spectrum.

The light-gathering capacity of a telescope depends on the area
of the main lens in the front, or the main mirror in the back.
That's also the area of the opening of the tube, called the 'aperture'.

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**PLEASE QUICKLY **A circuit has a resistance of 250 and is powered by a 120 V batteryThe current in the circuit, to the nearest tenth, is
____А.

Answers

Answer:

Current, I = 0.48 A

Explanation:

We have,

Resistance of a circuit is 250 ohms

Voltage of the battery is 120 V

It is required to find the current flowing in the circuit. Let I is the electric current. Ohm's law is given by :

V=IR\n\nI=(V)/(R)\n\nI=(120)/(250)\n\nI=0.48\ A

So, the current in the circuit is 0.48 A.

A train is accelerating at a rate of 2 km/hr/s.  If its initial velocity is 20 km/hr, what is its velocity after 30 seconds?

Answers

Here it is. *WARNING* VERY LONG ANSWER

________________________________________... 
11) If Galileo had dropped a 5.0 kg cannon ball to the ground from a height of 12 m, the change in PE of the cannon ball would have been product of mass(m),acceleration(g)and height(h) 

The change in PE =mgh=5*9.8*12=588 J 
______________________________________... 
12.) The 2000 Belmont Stakes winner, Commendable, ran the horse race at an average speed = v = 15.98 m/s. 

Commendable and jockey Pat Day had a combined mass =M= 550.0 kg, 

Their KE as they crossed the line=(1/2)Mv^2 

Their KE as they crossed the line=0.5*550*(15.98)^2 

Their KE as they crossed the line is 70224.11 J 

______________________________________... 
13)Brittany is changing the tire of her car on a steep hill of height =H= 20.0 m 

She trips and drops the spare tire of mass = m = 10.0 kg, 

The tire rolls down the hill with an intial speed = u = 2.00 m/s. 

The height of top of the next hill = h = 5.00 m 

Initial total mechanical energy =PE+KE=mgH+(1/2)mu^2 

Initial total mechanical energy =mgH+(1/2)mu^2 

Suppose the final speed at the top of second hill is v 

Final total mechanical energy =PE+KE=mgh+(1/2)mv^2 

As mechanical energy is conserved, 

Final total mechanical energy =Initial total mechanical energy 

mgh+(1/2)mv^2=mgH+(1/2)mu^2 

v = sq rt [u^2+2g(H-h)] 

v = sq rt [4+2*9.8(20-5)] 

v = sq rt 298 

v =17.2627 m/s 

The speed of the tire at the top of the next hill is 17.2627 m/s 
______________________________________... 
14.) A Mexican jumping bean jumps with the aid of a small worm that lives inside the bean. 

a.)The mass of bean = m = 2.0 g 

Height up to which the been jumps = h = 1.0 cm from hand 

Potential energy gained in reaching its highest point= mgh=1.96*10^-4 J or 1960 erg 

b.) The speed as the bean lands back in the palm of your hand =v=sq rt2gh =sqrt 0.196 =0.4427 m/s or 44.27 cm/s 
_____________________________ 
15.) A 500.-kg horse is standing at the top of a muddy hill on a rainy day. The hill is 100.0 m long with a vertical drop of 30.0 m. The pig slips and begins to slide down the hill. 

The pig's speed a the bottom of the hill = sq rt 2gh = sq rt 2*9.8*30 =sq rt 588 =24.249 m/s 
__________________________________ 
16.) While on the moon, the Apollo astronauts Neil Armstrong jumped up with an intitial speed 'u'of 1.51 m/s to a height 'h' of 0.700 m, 

The gravitational acceleration he experienced = u^2/2h = 2.2801 /(2*0.7) = 1.629 m/s^2 
______________________________________... 

EDIT 
1.) A train is accelerating at a rate = a = 2.0 km/hr/s. 

Acceleration 

Initial velocity = u = 20 km/hr, 

Velocity after 30 seconds = v = u + at 

Velocity after 30 seconds = v = 20 km/hr + 2 (km/hr/s)*30s = 

Velocity after 30 seconds = v = 20 km/hr + 60 km/hr = 80 km/ hr 

Velocity after 30 seconds = v = 80 km/hr=22.22 m/s 
_______________________________- 
2.) A runner achieves a velocity of 11.1 m/s 9 s after he begins. 

His acceleration = a =11.1/9=1.233 m/s^2 

Distance he covered = s = (1/2)at^2=49.95 m

Sound: The more _______ a sound has, the _________ its volume is.

Answers

First answer: vibrations Second: louder

Boyle’s Law: When____ is held constant, the pressure and volume of a gas are___ proportional.It didnt give me a word bank
No link answers please

Answers

Boyle’s Law states that, when temperature is held constant, the pressure and volume of a gas are inversely proportional.

What is meant by gas laws ?

Gas laws are defined as the laws that govern the properties of gases by determining the relationships between the pressure, volume and temperature of the gases.

Here,

Boyle's law is the gas law that governs the relationship between the pressure and volume of gases.

Boyle's law states that, for an ideal gas at a unit mass, the pressure of the gas is inversely proportional to the volume of the gas, at constant temperature.

P \alpha 1/V

PV = a constant

When the temperature of the gas is held constant.

Hence,

Boyle’s Law states that, when temperature is held constant, the pressure and volume of a gas are inversely proportional.

To learn more about gas laws, click:

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Answer:

When temperature is held constant, the pressure and volume of a gas are not proportional.

Explanation:

That is Boyle's Law

A child drags a 0.398 kg toy dogacross flat ground at constant speed,
with a 4.63 N force at a 63.0° angle.
What is the force of friction on the
toy?
(Hint: You do NOT need to know the
coefficient of friction.)

Answers

The force of friction on the toy is 2.10 N and it acts opposite to the direction of its motion.

What is friction?

A force called friction prevents one solid object from rolling or sliding over another. Although frictional forces, such the traction required to walk without slipping, may be advantageous, they can provide a significant amount of resistance to motion.

Given parameters:

mass of the toy dog: M = 0.398 kg.

Applied force: F = 4.63 N.

Angle of application of force: θ = 63.0°

Hence, horizontal component of applied force = F cosθ

= 4.63 × cos63.0° N

= 2.10 N.

As the child drags a 0.398 kg toy dog across flat ground at constant speed, this component of applied force is nullified by force of friction.

Hence,  the force of friction on the toy is 2.10 N and it acts opposite to the direction of its motion.

Learn more about friction here:

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Answer:

-2.1 N

Explanation:

What is Aristotle famous for?

Answers

Answer:

History

Explanation:

Im. Sorry. Im. Not. Much. Help