How many grams of water are produced when 2.50 mol oxygen reacts with hydrogen?

Answers

Answer 1
Answer:

Given:

2.5 mol O2

Required:

Grams of water

Solution:

2H2 + O2 -> 2H2O

Moles of H2O = (2.5 mol O2)(2moles H2O/1 mole O2) = 5 moles H2O

Molar mass of H2O = 18.02 g/mol

Mass of H2O = (5 moles H2O)( 18.02g/mol)

Mass of H2O =90.1g H2O


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A gas of 190 mL at a pressure of 74 atm can be expected to change its pressure when its volume changes to 30.0 mL. Express its new pressure in units of atmospheres.

Answers

Answer : The new pressure of the gas will be, 468.66 atm

Explanation :

Boyle's Law : This law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto (1)/(V)     (At constant temperature and number of moles)

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure of the gas = 74 atm

P_2 = final pressure of the gas = ?

V_1 = initial volume of the gas = 190 ml

V_2 = final volume of the gas = 30 ml

Now we put all the given values in the above formula, we get the final or new pressure of the gas.

74atm* 190ml=P_2* 30ml

P_2=468.66atm

Therefore, the new pressure of the gas will be, 468.66 atm

Answer: The new pressure of the gas is 467 atm.

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=74atm\nV_1=190mL\nP_2=?atm\nV_2=30.0mL

Putting values in above equation, we get:

74atm* 190mL=P_2* 30.0mL\n\nP_2=(74* 190)/(30.0)=467atm

Hence, the new pressure of the gas is 467 atm.

If the atomic radius of a calcium crystal is 180 pm, what is the length of the edge of the unit cell? (the calcium crystal forms

Answers

The edge length of a a unit cell of calcium crystal is 509.12 pm.

Structure of the Calcium crystals

Calcium crystal has a face center cubic (FCC) structure.

Edge length of the unit cell

The edge length of the unit cell for face center cubic (FCC) structure is given in the following formula;

a = 2r√2

where;

  • a is edge length
  • r is the radius

a = 2 x 180 x √2

a = 509.12 pm

Thus, the edge length of a a unit cell of calcium crystal is 509.12 pm.

Learn more about edge length here: brainly.com/question/11796119

Calcium crystal has a face center cubic (FCC) structure. For FCC structure,
relation between edge length (a) and radius (r) is
                                                       a = 2
√2 r
Given: r = 180 pm
Therefore, a = 2
√2 180
                     = 2 x 1.141 x 180
                     = 410.76 pm

The length of the edge of the Ca unit cell is 410.76 pm.

 

Elements in the same vertical column share similar chemical properties. Which statement best explains this?a. They have the same number of neutrons in their nucleus.
b. They have similar physical qualities.
c. They have identical numbers of electrons in the outermost level.
d. They were discovered in the same location.

Answers

they have identical numbers of electrons in the outermost level
Answer:C

Explanation:Most vertical columns share similiar chemical properties because they have identical numbers of electrons in the outermost level.

Hope this helped:)

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Answers

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Atoms of different isotopes of the same element differ in their total number of electrons neutrons protons valence electrons

Answers

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Describe your accuracy of your density measurements asummunf that you correctly identified your mystery solid and liquid

Answers

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