Consider the unbalanced equation for the combustion of hexane:2C6H14(g)+19O2(g)→12CO2(g)+14H2O(g)Determine how many moles of O2 are required to react completely with 7.9 moles C6H14.

Answers

Answer 1

Answer:

The balanced equation is C6H14(g) + 19/2O2(g) → 6CO2(g) + 7H2O(g). If you are given 7.9 moles C6H14, multiply it by a ratio of 19/2/1 to get the moles of oxygen. Then, you will get 75.05 moles of O2.

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Radical chlorination of pentane is a poor way to prepare 1-chloropentane, but radical chlorination of neopentane, (CH3)4C, is a good way to prepare neopentyl chloride, (CH3)3CCH2Cl. Why? ...?

Answers

Because it’s random that CH3CH2CH2CH2CH3 losing a (·H), so by reaction with Cl2, it canform many isomers, such as CH3CH2CH2CHClCH3, CH3CH2CHClCH2CH3,CH3CH2CH2CH2CH2Cl, so a poor way to prepare 1-chloropentane.While for (CH3)4C, each of the H atom are equivalent. So no matter which one be substituted,only one product, (CH3)CCH2Cl, can be prepared.

Final answer:

Radical chlorination of pentane and neopentane results in different yields of the desired products due to the selectivity of the reaction. With neopentane, the reaction is very selective, producing a higher yield of neopentyl chloride, while with pentane, the reaction isn't selective, leading to various isomers and a lower yield of 1-chloropentane.

Explanation:

Radical chlorination of pentane isn't an efficient method to prepare 1-chloropentane because it doesn't give a high yield of the desired product. This is due to it being a non-selective process, leading to the formation of several isomeric products. In the case of pentane, several different hydrogens can be replaced creating many possible isomers of chloropentane.

On the other hand, radical chlorination of neopentane or (CH3)4C is a good way to prepare neopentyl chloride or (CH3)3CCH2Cl. This is because neopentane has a far greater proportion of equivalent tertiary hydrogens. When chlorination occurs, it's most likely to happen at these sites, producing a higher yield of the desired neopentyl chloride product with less chance of isomer formation.

This difference is due to the selectivity and specificity of the radical chlorination reaction on neopentane versus pentane. Radical chlorination is not very selective with pentane but is quite selective with neopentane due to the type of hydrogens present, thus making it a more ideal reaction.

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Consider the mixture of ethanol, c2h5oh, and o2. how many molecules of co2, h2o, c2h5oh, and o2 will be present if the reaction goes to completion?

Answers

The reaction between ethanol and oxygen must be a combustion reaction to give carbon dioxide and water as products.

The reaction between ethanol, $C_2H_5OH$ and oxygen, $O_2$ is as follows:

$C_2H_5OH+O_2\rightarrow CO_2+H_2O$

In order to balance the reaction (the number of atoms of each element in the reaction are same on both the sides that is product and reactant), $O_2$ is multiplied by 3 in the reactant side and $CO_2$ is multiplied by 2 and $H_2O$ is multiplied by 3 on product side.

So, the balanced reaction is:

$C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O$

From the balanced reaction it is clear that 1 mole of $C_2H_5OH$ reacts with 3 moles of $O_2$ to give 2 moles of $CO_2$ and 3 moles of $H_2O$ .

Since, 1 mole = $6.022* 10^(23)$ molecules (Avogadro's number)

So,

Number of molecules of $C_2H_5OH$ = $6.022* 10^(23)$ molecules.

Number of molecules of $O_2$ = $6.022* 10^(23)* 3 = 18.066* 10^(23)$ molecules.

Number of molecules of $CO_2$ = $6.022* 10^(23)* 2 = 12.044* 10^(23)$ molecules.

Number of molecules of $H_2O$ = $6.022* 10^(23)* 3 = 18.066* 10^(23)$ molecules.

Answer : The number of molecules of $CO_2,H_2O,C_2H_5OH\text{ and }O_2$ are 2, 3, 1 and 3 respectively.

Explanation :

The given balanced chemical reaction is,

$C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O$

Balanced chemical reaction is the reaction in which the number of atoms of an individual elements present on reactant side must be equal to the product side.

The species present on the left side of the right arrow is the reactant and the species present on the right side of the right arrow is the product.

From the balanced chemical reaction, we conclude that there are 1 molecule of $C_2H_5OH$ , 3 molecules of $O_2$ , 2 molecules of $CO_2$ and 3 molecules of $H_2O$ .

Which statement must be true for any chemical reaction at equilibrium?(1) The concentration of the products is greater than the concentration of the reactants.
(2) The concentration of the products is less than the concentration of the reactants.
(3) The concentration of the products and the concentration of the reactants are equal.
(4) The concentration of the products and the concentration of the reactants are constant.

Answers

The correct answer is 3. The concentration of the product and the concentration of the reactants are equal. That is because matter cannot be created or destroyed and the product cannot randomly become something else in the reaction, nor can a reactant change into something different. Simply put, you cannot turn things like water into gold because there will always be an equilibrium.

Answer:

Answer is 4 The concentration of the products and the concentration of the reactants are constant.

Explanation:

Which statement must be true about a chemical system at equilibrium?(1) The forward and reverse reactions stop.
(2) The concentration of reactants and products are equal.
(3) The rate of the forward reaction is equal to the rate of the reverse reaction.
(4) The number of moles of reactants is equal to the number of moles of product.

Answers

(1) is wrong because at equilibrium both the reactant and the product are still being created they are just being created at the same rate meaning that

(3) is the answer. As the concentrations do not change, but the solution/system is still in dynamic equilibrium.

I agree with the answer below (partial credit would go to her/him I guess)
My answer I guess is more visual to explain
1 says --> | <--
2 is assuming because not all chemical system are the same although this could be true in some cases
3 says --> which is true because that's the def of Equilibrium
<--
4-I don't get that one-sorry

Which of these statement is conclusive evidence that mixing sugar in water is a physical change? A). there is no change in color B).there is no precipitate formed. C).there is no gas given off. D).there is no molecular change.

Answers

The statement is conclusive evidence that mixing sugar in water is a physical change is there is no molecular change. Therefore, option D is correct.

What is physical change ?

A change known as physical change occurs when the physical characteristics of matter change. Physical changes include those in color, odor, solubility, and the condition of matter, among others.

Melting, turning into a gas, changing strength or durability, changing crystal structure or texture, and changing shape, size, color, volume, or density are a few examples of physical qualities.

Because sugar molecules are spread throughout the water, but the individual sugar molecules remain unaltered, dissolving sugar in water represents a physical change.

Thus, option D is correct.

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D.) There is no molecular change

Balance copper(II)sulfate+ammonium sulfide= copper(II) sulfide + ammonium sulfate

Answers

Final answer:

The balanced chemical equation for the reaction between copper(II) sulfate and ammonium sulfide is CuSO4 + (NH4)2S → CuS + (NH4)2SO4.

Explanation:

The balanced chemical equation for the reaction between copper(II) sulfate and ammonium sulfide is:

CuSO4 + (NH4)2S → CuS + (NH4)2SO4

This equation shows that when copper(II) sulfate (CuSO4) reacts with ammonium sulfide ((NH4)2S), copper(II) sulfide (CuS) and ammonium sulfate ((NH4)2SO4) are formed.

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Final answer:

The chemical reaction between copper(II) sulfate and ammonium sulfide producing copper(II) sulfide and ammonium sulfate is balanced when written as CuSO4 + (NH4)2S → CuS + (NH4)2SO4. This adheres to the principle of conservation of mass, ensuring an equal number of each type of atom on both sides.

Explanation:

The balancing chemical equation in question, copper(II)sulfate + ammonium sulfide = copper(II) sulfide + ammonium sulfate, starts off with the substances copper(II) sulfate and ammonium sulfide on the left side of the equation. In the process being described, these compounds engage in a chemical reaction, resulting in the formation of new substances, copper(II) sulfide and ammonium sulfate, which are represented on the right side of the equation. The balanced form of this equation is: CuSO4 + (NH4)2S → CuS + (NH4)2SO4.

An important concept in Chemistry is the principle of conservation of mass, which states that the total mass of substances does not change during a chemical reaction. Therefore, for a chemical equation to be balanced, there must be an equal number of each type of atom on both the left and right sides of the equation.

Applying this to the equation, we have 1 atom of copper (Cu), 1 atom of sulfur (S), 4 atoms of oxygen (O), 2 atoms of nitrogen (N), and 8 atoms of hydrogen (H) on both sides of the equation, which confirms that it is properly balanced.

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