One of the last questions for today and for 20 points!
one of the last questions for today and for 20 - 1

Answers

Answer 1
Answer: The y intercept is when x is 0.
y=7500(.97)^0
y=7500*1           (anything to the power 0 is 1)
y=7500
Y-intercept = (0,7500)
It represents the years when there wasn't an inactive account. There was no inactivity in the account.

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Which two square numbers have a difference of 51?

Answers

The question is asking to state the two square numbers that have a difference of 51, base on my calculation and further research, the possible numbers are 100 and 49, 100 is 10^2, while 49 is 7^2. I hope you are satisfied with my answer and feel free to ask for more 

Joshua has to earn more than 92 points on the state test in order to qualify for an academic scholarship. Each question is worth 4 points, and the test has a total of 30 questions. Let x represent the number of test questions.Which of the following inequalities can be solved to determine the number of questions Joshua must answer correctly?a. 4x < 30
b. 4x < 92
c. 4x > 30
d. 4x > 92

Answers

x-represent\ the\ number\ of\ test\ questions\n4x-the\ number\ of\ earned\ points\n \nJoshua\ has\ to\ earn\ more\ than\ 92\ points\n \n4x>92\ \ \ \Rightarrow\ \ \ Ans.\ d

What is the area of this regular polygon a 16.8 b 23.4 c 46.8 d 49.2

Answers

There we multiply by 6 because there are six sides in a polygon
6* (2.6*3/2)
= 6* 3.9
= 23.4
Therefore the answer will be option b (23.4)
Hope it helped you.
If it helped please mark as the brainliest answer.

Whole numbers greater than 6 but less than 16

Answers

8,7,9 can be greater than 6 but less than 16
6 is greater than 1,2,3,4,and 5 but 6 is not greater than 16

Select ALL of the expressions that are equivalent to
16 (5)/(2)

Answers

Answer:

A, B, C

Step-by-step explanation:

a^(m)/(n)=\sqrt[n]{a^m}\n\n(a^n)^m=a^(nm)\n\na^n\cdot a^m=a^(n+m)\n\n========================

16^(5)/(2)=\sqrt[2]{16^5}=√(16^5)\to\boxed{B}\n\n16=4^2\to16^(5)/(2)=\left(4^2\right)^(5)/(2)=4^{2\cdot(5)/(2)}=4^5\to\boxed{A}\n\n16^(5)/(2)=16^{2(1)/(2)}=16^{2+(1)/(2)}=16^2\cdot16^(1)/(2)=\left(16^2\right)\left(16^(1)/(2)\right)\to\boxed{C}

4a+4a-4a+b waht is the southion

Answers

I guess it is 3a + b, that is the only answer with the information given.