Jan and Laura have a total of 3 same sized cookies they want to divide equally between the two of them. What fraction of the cookies should each girl receive?

Answers

Answer 1
Answer: There are three cookies and two girls. So divide the number of cookies over the number of people who want equal shares.
3/2 or 1 1/2
Each girl gets one and a half cookies.

Hope this helps :)
Answer 2
Answer: Its 3 over 3 and it equals 1 because its an equal fraction so each of them get 1.

Related Questions

I need helpppppp ASAP
Round the number 347 500 to the nearest 1000, 10 000 and 100 000
Maddie bought 10 quarts of ice cream how many gallons and quarts of ice cream did madie buy explain how you found your answer
What is the answer for this question -12(-3)+7
I need help on this question

explain how you can use multiplication to find the quotient 3/5 divided by 3/15. then evaluate the expression

Answers

we  know that

Dividing is the opposite of multiplying. Therefore, dividing by a fraction can be accomplished by multiplying by its reciprocal

so

((a)/(b))/((c)/(d)) =(a)/(b)*(d)/(c)

in this problem we have

(a)/(b)=(3)/(5)\n \n(c)/(d)=(3)/(15)

substitute in the formula above

((3)/(5))/((3)/(15)) =(3)/(5)*(15)/(3)=3

therefore

the answer is

3

(3)/(5) ÷ (3)/(15)

(3)/(5) × (15)/(3) = (45)/(15) = 3

The midpoint of the line segment from p1 to p2 is (-2,4). If p1=(-5,6), what is p2?

Answers

-5 to -2 is 3 units. Go 3 units farther and end up with 1.
6 to 4 is 2 units. Go 2 units farther and end up with 2.
Answer (1,2)

Answer:

P2 is (1, 2).

Step-by-step explanation:

The x values of the midpoint and P1 are - 2 and -5 . That is P1 is 3 to the left of the midpoint.

The y values of the midpoint and P1 are  4 and 6 . That is P1 is 2 up from the mid -2point.

So P2 has an x coordinate of  3 to the right of the midpoint and a y coordinate of 2 down from the mispoint.

So P2 is (-2+3), (4 -2)

= (1, 2).

What is 127km  to the nearest 10km

Answers

127 rounded to the nearest 10 is 130 .

The ' 10s ' on each side of it are 120 and 130.
It's closer to 130.

You can tell that by looking at the units place.
If the units digit is less than 5, then it's closer to the lower ten.
If the units digit is 5 or more, then it's closer to the higher ten.
This units digit is 7, so it's closer to the higher ten . . . 130 .
127km = 130km since 7 in the tens digit is nearer to the 30 than 20 :)

Kira measures the round temperature dial on a thermostat and calculates that it has a circumference of 13.188 centimeters. What is the dial's radius?

Answers

C = 2*pi*r
r = C/2pi
= 13.188/2pi 
= 2.10 cm

Paul is taking inventory of unsold ladies’ dresses from last month. The following matrix shows how many of each dress were left in red, blue, white, and green. The matrix below shows the new stock of the same color dresses that arrived in the store today. Which matrix shows the total number of dresses of each color and size that Paul has in stock before any sales were made today?

Answers

Answer:

A

Step-by-step explanation:

Just add both matrices

Based on the number of dresses in stock, and the new stock that arrived, the matrix that showed the total number of dresses that Paul had in stock before sales is attached.

Which matrix shows the number of dresses before sales?

You can find this out by adding the numbers in the Matix before the new stock arrived, to the matrix that shows the new stock.

Sum the numbers in each position to get the new quantity:

= Small red + Small red new stock

= 2 + 3

= 5

= Medium Blue + Medium blue new stock

= 0 + 4

= 4

= White Large + White large new stock

= 3 + 1

= 4

Do this for all of them.

The new matrix is shown attached.  

Find out more on matrixes at brainly.com/question/1821869.

#SPJ2

Explain hard to tell whether (2,-1) is a solution of the equation Y= 3X -2 without using the graph

Answers

Answer:

Considering the equation given:

y= 3x -2

As a function:

f(x)= 3x -2

$(2, -1)$ states for (x, y), which means, x=2 and y=-1

f(2)= 3(2) -2\nf(2)= 6-2\nf(2)= 4

4\neq -1

Therefore, $(2, -1)$ is not a solution for the equation given and for the function.