An animal gained 4 pounds steadily over 16 years what is the unit of rate of pounds per year?

Answers

Answer 1

Answer: Think about it... If it gains 4 pounds in 16 years, how many does it grow in 1 year? :) See the relation? If not...

a) How would you express it growing per year? 4 pounds in 16 years... It must be 4/16!
b) To find the unit rate, the numerator MUST BE 1. What can you do to 4 to get to 1? You can divide by 4!
c) Of course, whatever you do to one side of the fraction, you HAVE to do to the other. That means you have to divide the 4 in the equation by 4 AND the 16 in the equation by 4. You should get 1/4, because 4/4 is 1 and 16/4 is 4.
d) Wow! That means your unit rate is 1 pound per 4 years, or 1/4!

TIP:
Try thinking of the division sign / as 'per'. Instead of the unit rate being thought of as 1/4, think of it as 1 per 4 years. :)

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Marty lives 2/3 mile from school. Linda lives 3/4 as far from school as Marty does. how far does Linda live from school?

Complete the equation of the line through (-10,3) and (-8,-8)Use exact numbers.
y=mx+b format
thank you (:

Answers

opps sorry its corrct but it is y= -11/2x - 52

$\bf (\stackrel{x_1}{-10}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{-8})\n\n\n% slope = mslope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-3}{-8-(-10)}\implies \cfrac{-8-3}{-8+10}\implies \cfrac{-11}{2}\n\n\n% point-slope intercept\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=-\cfrac{11}{2}[x-(-10)]\n\n\ny-3=-\cfrac{11}{2}(x+10)\implies y-3=-\cfrac{11}{2}x-55\implies y=-\cfrac{11}{2}x-52$

A bicycle rider travels 50.0 km i. 2.5 hours. what is a cyclists average speed

Answers

If you divide the bumbers you will get on acerage of 20km

1. Measures of CenterLions: 14, 13, 31, 21, 24, 19Jets scores: 15, 17, 13, 6, 26, 21Which team had a higher medianscore? By how much?

Answers

Lions
because if you find the median in both there will be two medians so that means you have to add up the two medians.

For the first one the medians were 31 and 21 so add 31+21=52 and 52/2=26

For the second one the medians were 13 and 6 so add 13+6=19 and 19/2=9.5

So the higher score woud be lions and it would by higher by 16.5
hope this helped:)

15% of Alina’s workout consisted of cardio exercise. 25% of Dane’s workout consisted of cardio exercise. Which statement must be true?If they worked out for the same amount of time, Dane did 10 more minutes of cardio exercise than Alina.

If Alina’s workout was 80 minutes, and Dane’s workout was 48 minutes, they spent the same amount of time on cardio exercise.

If both workouts were 60 minutes, Dane spent 8 more minutes on cardio exercise than Alina did.

Alina spent less time on cardio exercise than Dane did.

Answers

The correct answer is B. If Alina’s workout was 80 minutes, and Dane’s workout was 48 minutes, they spent the same amount of time on cardio exercise.

To figure this out, first find 15% of 80 and then 25% of 48.

To find 15% of 80, you can first find 10% of 80 which is 8(just move the decimal one place to the left). The remaining 5% will be half of 8 since 8 is 10%. Add both the numbers up and you will get 12. (8+4=12)

To find 25% of 48, you can divide 48 by 4. Since percent means 'out of 100', 25% is 25 of 100. 100 divided by 25 is equal to 4. So, 48 divided by 4 is equal to 12.

So, the final answer is B. They both equal to 12.

Hope it helps :)

Sandy has box of chocolates. Box cost $2.00. In box has 8 chocolates. How much does each chocolate cost.

Answers

so you must find individual prices.

Start by doing the price($2.00)divided by the amount in box(8)

you should get 0.25 or 25 cents per chocolate

Divide $2.00 by 8 and your answer is $0.25

7/10 in a decimal????? ¡

Answers

7/10 is just 0.7 as a decimal

.7 since 7 divided by 10 is .7 :)

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calvin paints pictures and sells them at art shows. He charges $56.25 for a large painting. He charges $25.80 for a small painting. Last month he sold six large paintings and three small paintings. How much did he make in all?