If 28% of a sum is $100.80, what is the sum? A. $360.00
B. $282.24
C. $277.78
D. $129.02

Answers

Answer 1

Answer: 28% of x = 100.80
.28 × x = 100.80
.28x = 100.80
x = 100.80/.28
x = 360

Answer A

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For today’s lunch, a school cafeteria’s budget allows it to purchase at most 60 cans of beans and 45 cans of corn. 1 can of beans feeds 5 students, and 1 can of corn feeds 6 students. Each student will have beans or corn, but not both, and there will be a maximum of 420 students at lunch. If a can of beans cost $2.00 and a can of corn cost $3.00, what is the maximum amount of money required to feed all of the students either beans or corn?A: $180

B: $195

C: $210

D: $225

Answers

Answer:

Option B.

Step-by-step explanation:

Let x be the number of cans of beans and y be the number of cans of corn.

Cafeteria’s budget allows it to purchase at most 60 cans of beans and 45 cans of corn.

$x\leq 60$

$y\leq 45$

1 can of beans feeds 5 students, and 1 can of corn feeds 6 students. Each student will have beans or corn, but not both, and there will be a maximum of 420 students at lunch.

$5x+6y\leq 420$

Can of beans cost $2.00 and a can of corn cost $3.00.

Objective function, Z=2x+3y

The required linear programming problem is

Objective function, Z=2x+3y

Subject to the constraints

$x\leq 60$

$y\leq 45$

$5x+6y\leq 420$

$x\geq 0, y\geq 0$ (Only 1st quadrant)

Draw the graph of these constraints as shown below.

The verities of common shaded region are (0,45), (30,45), (60,20), (60,0), (0,0).

Points Z=2x+3y

(0,0) 0

(0,45) 135

(30,45) 195

(60,20) 180

(60,0) 120

The maximum amount of money required to feed all of the students either beans or corn is $195.

Number of cans of beans = 30

Number of cans of corn = 45

Therefore, the correct option is B.

I would go with B, one hundred ninety five dollars. Hope that this would help you..

Which statement is Hypothesis?If a and b are odd, then a*b is odd

A: if a*b is odd than a and b are odd
B: if a and b are odd, than a*b is odd
C: a*b is odd
D: a and b are odd

Answers

a because it is the right answer

At what times of the day between 10:00 A.M. and 5:00 P.M. do the chemistry presentation and the recycling presentation start at the same time? SCIENCE MUSEUM
-Show Schedule-
Chemistry-Every 10 minutes
Electricity-Every 20 minutes
Recycling-Every 6 minutes
Fossils-Every 45 minutes

The first showing for all shows is at 10:00 A.M.

Answers

Okay, Chemistry runs every 10 minutes and the Recycling runs every 6 minutes. In order to find what time they both start at the same time you must find the lowest common multiple (if you are using mathematical terminology). To do this the long but visual way you can write out each of the times and find the first ones that are the same.
Chemistry: 10:00 10:10 10:20 10:30
Recycling: 10:00 10:06 10:12 10:18 10:24 10:30
As you can see both Chemistry and Recycling both have a LCM of 10:30 which tells us that the time for which both Chemistry and Recycling start at the same time during the show is 10:30AM.

Final answer:

The chemistry and recycling presentations coincide every 30 minutes starting from 10:00 A.M. They will occur at the same time at 10:30 A.M., 11:00 A.M., 11:30 A.M., etc., until 5:00 P.M.

Explanation:

To solve this problem, we need to find the common multiple of 10 and 6, which is the frequency in minutes of the chemistry and recycling presentations respectively. The least common multiple (LCM) of 10 and 6 is 30. So, the chemistry and recycling presentations will coincide every 30 minutes.

Starting at 10:00 A.M., they would coincide at 10:30 A.M., 11:00 A.M., 11:30 A.M., and continue in this pattern until 5:00 P.M.

Learn more about least common multiple here:

brainly.com/question/34291727

#SPJ11

Identify the property illustrated by 3x + 4 = 4 + 3x

Answers

Explanation:

Answer:
All real numbers are solutions

Answer:

All real numbers are solutions

Step-by-step explanation:

What are the roots of the equation x2 + 4x - 16 = 0?

Answers

see attached picture for answer

Find an equation for the family of linear functions with slope 2 and sketch several members of the family

Answers

f(x)=2x+b. the general eqtn is y=2x+b where b can be +ve or -ve. If you draw y = 2x, you get a line of slope 2, passing through the origin. The line y = 2x+3 is parallel to y = 2x, and cuts the y-axis at y = 3. Similarly, the line y = 2x-1 is parallel to y = 2x, and cuts the y-axis at y = -1. You do not need any points to sketch them on our graph: the lines you draw must just be parallel to y = 2x

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