A video game randomly chooses your car color and type. The probability of getting a red car is 0.20, and the probability of getting a convertible is 0.40.Event A = You get a red car.
Event B = You get a convertible.
A and B are independent events if _____.
A.The probability of getting a red car or a convertible is 0.60.
B.The probability of getting a red car or a convertible is 0.08.
C.The probability of getting a red convertible is 0
D.The probability of getting a red convertible is 0.08
Answers
Answer: Option 'D' is correct.
Step-by-step explanation:
Since we have given that
Event A: You get a red car
and
Similarly,
Event B: You get a convertible
and
So, if A and B are independent , then they must satisfy,
So,
Hence, Option 'D' is correct, which states that the probability of getting a red convertible is 0.08.
Answer:
D.The probability of getting a red convertible is 0.08
Step-by-step explanation:
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Select the correct solution set. -7x ≥ 56 {x | x ≤ -8} {x | x ≥ -8} {x | x ≥ 8}
ANSWER ASAP FOR BRAINLIESTT
A shoemaker bought 30 pairs of heels. How many individual heels did the shoemaker buy?a. 60 b. 15 c. 30 d. 120
Write an equation in slope - intercept form passing through (2,5); slope 3 over 4
Answers
Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
Answers
Answer:
A≈31415.93cm²
Step-by-step explanation:
Answers
Answer:
wheres A though? Try to provide a picture or something.
B) Yes. P(married and exercise in the morning) = P(married)·P(exercise in the morning) = 45%
C) No. P(married and exercise in the morning) = 60% & P(married)·P(exercise in the morning) = 42%
D) No. P(married and exercise in the morning) = 45% & P(married)·P(exercise in the morning) = 34.2%
Answers
Women only gym:
60% married women
75% of the married women exercise in the morning
30% of the single women exercise in the morning
60% married women + 40% single women = total women members
60% married
75% exercise in the morning
25% exercise in the afternoon or evening
40% single
30% exercise in the morning
70% exercise in the afternoon or evening
Exercise in the morning
married: 60% x 75% = 45%
single: 40% x 30% = 12%
B) Yes. P(married and exercise in the morning) = P(married)·P(exercise in the morning) = 45%
Answer:
D) No. P(married and exercise in the morning) = 45% & P(married)·P(exercise in the morning) = 34.2%
Step-by-step explanation:
Answers
x = width
x + 6 = length
perimeter = length + length + width + width
x + x + x + 6 + x + 6 = 44
4x + 12 = 44
4x = 32
x = 32/4
x = 8
width = 8 meters
length = 8 + 6 = 14 meters
Answers
Answer:
THERE
Step-by-step explanation:
a) To determine how far each ostrich ran, we need to calculate the area under the velocity-time graph for each ostrich. Since the graph represents velocity, the area under the graph represents the distance traveled.
For Ostrich Bert:
The area under the graph can be divided into two sections: a triangle and a rectangle. The triangle's base is 3 seconds and its height is 18 m/s, so its area is (1/2) * 3 * 18 = 27 m. The rectangle has a base of 2 seconds and a height of 9 m/s, so its area is 2 * 9 = 18 m. Adding the areas together, Bert ran a total distance of 27 + 18 = 45 meters.
For Ostrich Ernie:
The area under the graph can also be divided into two sections: a triangle and a rectangle. The triangle's base is 4 seconds and its height is 12 m/s, so its area is (1/2) * 4 * 12 = 24 m. The rectangle has a base of 2 seconds and a height of 6 m/s, so its area is 2 * 6 = 12 m. Adding the areas together, Ernie ran a total distance of 24 + 12 = 36 meters.
b) To calculate the average velocity of Bert, we need to divide the total distance he ran (45 meters) by the total time it took (5 seconds). Therefore, Bert's average velocity is 45 meters / 5 seconds = 9 m/s.
c) The initial acceleration of Ernie can be determined by finding the slope of the velocity-time graph during the initial portion. From the graph, we can see that Ernie's velocity increases by 6 m/s over the first 2 seconds. Therefore, his initial acceleration is (change in velocity) / (change in time) = 6 m/s / 2 seconds = 3 m/s^2.
d) Without further calculation, we can determine that Ernie had the greatest initial acceleration. This is because Ernie's velocity increases at a steeper slope during the initial part of the graph compared to Bert's velocity. The greater the slope, the greater the acceleration. Therefore, Ernie had the greatest initial acceleration.