A failure of the red-sensitive nerves in the eye to respond to light properly causes A. astigmatism.
B. farsightedness.
C. chromatic aberration.
D. color blindness.

Answers

Answer 1

Answer: D. colour blindness

"red-sensitive" just means that the nerves are able to see red light

Answer 2

Answer:

D. Color blindness is your correct answer

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Which two of the following actions would result in a guitar string sounding a lower note
when plucked?
A Loosening the string
B Tightening the string
C Shortening the string
D Using a heavier string

Answers

Answer is d using a heavier string

1) Un perito fue encomendado para determinar si un trozo de metal muy parecido al oro de 0,75 kg. Y de volumen 340 cm3. Era en verdad dicho metal, use las características de la densidad de un cuerpo para ayudar al perito.

Answers

Answer:

Primero, sabemos que la densidad de el oro es:

Densidad = 19.3 g/cm^3

Sabemos que nuestro metal tiene una masa de 0.75 kg, y un volumen de 340 cm^3.

Primero deberíamos reescribir la masa en gramos, pues la densidad está escrita en gramos.

Sabemos que:

1 kg = 1000g

Entonces:

0.75 kg es 0.75 veces 1000g, esto nos da:

0.75kg = 0.75*(1000g) = 750g

Entonces tenemos:

masa = 750g

volumen = 340cm^3

Ahora debemos recordar que:

densidad = masa/volumen

Entonces la densidad de este metal es:

densidad = 750g/340cm^3 = 2.21 g/cm^3

Si la comparamos con la densidad del oro, podemos ver que esta es mayor.

Entonces podemos concluir que este metal no es oro.

1 Determine the wavelength, frequency, and amplitude for each wave.2. Sprays as
Summarize it!
c The
Time Elapsed: 45
D
-0.5 m
10 m
15 m
20 m
0.5 m
I. 0.5 m

Answers

Answer:

cbccfggssdaffzftyrd

How to find the period of a wave

Answers

The method to choose depends on what information you have, and
on what you can measure. Here are a few possible methods:

-- Measure the period. Start your clock when one peak
of the wave passes you. Stop the clock when the next
peak passes you. The time between the two peaks is
the wave's period.

-- Divide the wave's wavelength by its speed. That quotient
is the wave's period.

-- Use an electronic frequency meter to measure the wave's
frequency. Then take its reciprocal (divide ' 1 ' by it). The
result is the wave's period.

In one hand you hold a .12-kg apple, in the other hand a .20-kg orange. The apple and orange are separated by .75 m. What is the magnitude of the force of gravity that
(a) the orange exerts on the apple?
(b) the apple exerts on the orange?

Answers

Final answer:

The orange exerts a gravitational force on the apple, which can be calculated using the formula for gravitational force. The apple exerts an equal and opposite gravitational force on the orange.

Explanation:

(a) The orange exerts a gravitational force on the apple. The magnitude of this force can be calculated using the formula for gravitational force: F = G * (m1 * m2) / r^2, where G is the gravitational constant (approximately 6.67430 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass. Plugging in the values, we have F = (6.67430 x 10^-11 N*m^2/kg^2) * (0.12 kg * 0.20 kg) / (0.75 m)^2. Solving this equation gives us the magnitude of the force of gravity between the orange and apple.

(b) The apple exerts an equal and opposite gravitational force on the orange, as described by Newton's third law of motion. This means that the magnitude of the force of gravity exerted by the apple on the orange is the same as the force of gravity exerted by the orange on the apple.

Learn more about Gravitational force here:

brainly.com/question/32609171

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Final answer:

The force of gravity between two objects can be calculated using Newton's universal law of gravitation. The force the orange exerts on the apple, and vice versa, is 2.138 x 10^-11 N. However, the apple's force on the orange is in the opposite direction.

Explanation:

The subject of this question is gravity, a fundamental force in physics. The force of gravity between two objects can be calculated using Newton's law of universal gravitation, which states that every point mass attracts every other point mass by a force pointing along the line intersecting both points. The equation is F = G * ((m1*m2)/r^2), where F is the force of gravity between the two objects, G is the gravitational constant (6.674 x 10^-11 N(m/kg)^2), m1 and m2 are the masses of the objects, and r is the distance between the centers of the two objects.

(a) Using this equation, we can find that the force the orange exerts on the apple is F = (6.674 x 10^-11) * ((0.20*0.12)/0.75^2) = 2.138 x 10^-11 N.

(b) According to Newton's third law of motion, every action has an equal and opposite reaction. Thus, the force the apple exerts on the orange is equal in magnitude and opposite in direction to the force the orange exerts on the apple, or -2.138 x 10^-11 N. The negative sign indicates that this force is in the opposite direction.