Write the equation of the line that contains the given point and has the given slope. (–1, 4), slope is –3

Answers

Answer 1
Answer:

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{4})~\hspace{10em}slope = m\implies -3\n\n\n \begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\n\cline{1-1}\ny-y_1=m(x-x_1)\n\n\cline{1-1}\end{array}\implies y-4=-3[x-(-1)]\n\n\ny-4=-3(x+1)\implies y-4=-3x-3\implies y=-3x+1

Answer 2
Answer: Y = -3x + 4. This is because the y value is -4 so that would be the y intercept and -3 is the slope as said in the question

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When the sum of a number plus 3 is squared it is 11 more than the sum of the number plus 2 when squared.

Answers

x-number\n\n (x+3)^2-11=(x+2)^2\n\n x^2+2*3*x+3^2-11=x^2+2*2*x+4\n\n x^2+6x+9-11=x^2+4x+4\ \ |-x^2\n\n6x-2=4x+4\n\n6x-4x=4+2\n\n2x=6\ \ |:2\n\n x=3

Answer quick for brainliest <3

Answers

Answer:

D

Step-by-step explanation:

A line has to be able to be straightly drawn though the points in order to be proportional

Find the x-intercept of the parabola with vertex (6,27) and y-intercept (0,-81)

Answers

The vertex form of the equation of a parabola with the vertex (h,k):
y=a(x-h)^2+k

The parabola has the vertex at (6,27).
y=a(x-6)^2+27

The y-intercept is (0,-81).
x=0, \ y=-81 \n\Downarrow \n-81=a(0-6)^2+27 \n-81=a(-6)^2+27 \n-81=36a+27 \n-81-27=36a \n-108=36a \n(-108)/(36)=a \na=-3

The equation of the parabola is:
y=-3(x-6)^2+27

y=0 at the x-intercepts.
0=-3(x-6)^2+27 \n-27=-3(x-6)^2 \n(-27)/(-3)=(x-6)^2 \n9=(x-6)^2 \n√(9)=√((x-6)^2) \n3=|x-6| \nx-6=3 \ \lor \ x-6=-3 \nx=3+6 \ \lor \ x=-3+6 \nx=9 \ \lor \ x=3

The x-intercepts are x=3 and x=9.

Please solve question 2.

Answers

Hello,

L=2W-3
and Area= (2W-3)W=77
==>2W²-3W-77=0

==> (W=7) or (W=-22/4 to exclude <0)
If W=7 then  2*W-3=14-3=11
Area=7*11=77

Photgraphy is 7 by 11  (cm)

What is the sum of the polynomials? ( 8x^2 -9y^2-4x) + (x^2- 3y^2- 7x) answer options are in the pics

Answers

Answer:  The correct option is (D) 9x^2-12y^2-11x.

Step-by-step explanation:  We are given to find the following sum of the polynomials :

S=(8x^2-9y^2-4x)+(x^2-3y^2-7x)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To find the required sum, we need to add the coefficients of the same unknown variables with equal powers.

The sum of the polynomials in (i) is as follows :

S\n\n=(8x^2-9y^2-4x)+(x^2-3y^2-7x)\n\n=8x^2-9y^2-4x+x^2-3y^2-7x\n\n=(8+1)x^2-(9+3)y^2-(4+7)x\n\n=9x^2-12y^2-11x.

Thus, the required sum of the polynomials is9x^2-12y^2-11x.

Option (D) is CORRECT.

(8x^2-9y^2-4x)+(x^2-3y^2-7x)

First, get rid of the parentheses and combine like terms

(8x^2+x^2)(-9y^2-3y^2)(-4x-7x)

9x^2-12y^2-11x is your answer

Which inequality will have a shaded area below the boundary line?

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Another twofer !

We don't know what the choices are, and we don't know where
the boundary line is.  Otherwise, the question is intriguing indeed.