Write the equation of the line, given the y- and x-intercepts. x-intercept (–6, 0), y-intercept (0, –8)

Answers

Answer 1

Answer:

neverminding for a second that they're intercepts at all, they're points on the line, so

$\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad(\stackrel{x_2}{0}~,~\stackrel{y_2}{-8})\n\n\n slope = m\implies\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-0}{0-(-6)}\implies \cfrac{-8-0}{0+6}\implies \cfrac{-8}{6}\implies -\cfrac{4}{3}\n\n\n \begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\n\cline{1-1}\ny-y_1=m(x-x_1)\n\n\cline{1-1}\end{array}\implies y-0=-\cfrac{4}{3}[x-(-6)]\n\n\ny=-\cfrac{4}{3}(x+6)\implies y=-\cfrac{4}{3}x-8$

Related Questions

Given a mean of 43.8 and a standard deviation of 8.7, what is the z-score of the value 40 rounded to the nearest tenth?
Subtract 3/y-2 - 1/y+3
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Amaya ran for president of chess club, and she received 18 by this. There were 30 members in the club. What percentage of the club members voted for Mýa HELP PLEASE

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Answers

x/4-9=5
x/4=14
x=14/4
x=7/2
x=3.5

What is the LCM of 3 and 7?

3
7
14
21

Answers

The correct answer is 21 simply because 21 is a multiple of 3 and a multiple of 7, other answer does not hold this conclusion.

Evaluate.
5 P 3 x 6 C 4

a. 150
b. 300
c. 900

Answers

Answer:

Option (c) is correct.

$^5P_3*^6C_4$ is 900

Step-by-step explanation:

Given :Expression $^5P_3*^6C_4$

We have to find the value of given expression $^5P_3*^6C_4$

Consider the given expression $^5P_3*^6C_4$

The possibility of choosing an ordered set of r object from n object is given by

$nPr=(n!)/(\left(n-r\right)!)$

and The number of subset of r elements from n elements $nCr=(n!)/(r!\left(n-r\right)!)$

Thus, $^5P_3=(5!)/(\left(5-3\right)!)==(5!)/(2!)=5\cdot \:4\cdot \:3=60$

and $^6C_4=(6!)/(4!\left(6-4\right)!)==(6!)/(4!\cdot \:2!)==(6\cdot \:5)/(2!)=15$

Thus, $^5P_3*^6C_4=60* 15=900$

Thus, $^5P_3*^6C_4$ is 900

The answer is 300 because if u x the 5x3=15 and divide 6 and 4 is 1.5 then multipy that 22 then you put the letters in the equations

Step 1: pick a number step 2: double it
step 3: add 5
step 4: multiply by 50
step 5: if you've had your birthday this year ,add 1764,or,if you've not yet had your birthday this year ,add 1763
step 6: subtract the year of your birth
you should end up with a number which is a combination of the number you started with followed with your age. for example ,if you are 12 and you start with the number 27, the result should be 2712.
your task :
1. let n represent the number in step 1 and show what happens through step 6.
2. explain why the result is always the original number followed by your age. What would be the expression I would use?

Answers

if I pick n, it becomes 50(2n+5)+1764-2001 this is the expression

Write 63.63% as a fraction

Answers

Answer:

6363/10000

Step-by-step explanation:

For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range.The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2.
The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2.
The vertex is (–1, 2), the domain is all real numbers, and the range is y ≥ 2.
The vertex is (–1, 2), the domain is all real numbers, and the range is y ≤ 2.

Answers

$f(x)=3(x-1)^2+2\ It's\ a\ quadratic\ function\n\ntherefore\ Domain:\boxed{D:x\in\mathbb{R}\ all\ real\ numbers}\n\nvertex:\nthe\ vertex\ form:\ y=a(x-h)^2+k\nwhere\ (h;\ k)h\ and\ k\ are\ the\ x\ and\ y\ coordinates\ of\ the\ vertex\n\boxed{vertex:(1;\ 2)}$
$range:\na=3 \ \textgreater \ 0\ therefore\ the\ parabola\ ope ns\ upward\nso\nrange\ is\ [vertex\ (y);\ infinity)\nrange:\boxed{y\geq2\y\in[2;\ \infty)}\n\nYour\ answer:\n\boxed{The\ vertex\ (1;\ 2);\ domain\ is\ all\ real\ number\ (x\in\mathbb{R});\ range\ y\geq2}$

$f(x)=3(x-1)^(2)+2 \n \n f(x)=a(x-p)^(2)+q \n \n W=(p,q) \n \n W=(1,2) \n \n D: x \in R \n \n a \ \textgreater \ 0 \n \n Range: y \in [2,+\infty)$

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