Does the point (2,3) lie on the line y=3/4x-2

Answers

Answer 1
Answer: No.

If you substitute x with 2 and y with 3, it doesn't equal meaning its not a point.

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ben the camel drinks tea (so classy!). he drinks 350 liters of tea every 2 days. how many liters of tea does ben drink every 6 days?

Answers

I think its 1050 liters . I divided the 350 liters by 3 .

If the base of a rectangle is 12cm and the area is 250.8cm2 what is the height of the rectangle

Answers

250.8cm^2/12cm= 20.9cm.
the height of the rectangle is 20.9 cm
250.8cm^2/12cm = 20.9cm
the height of the rectangle is 20.9cm

Which of the following numbers can be expressed as repeating decimals?2 over 9, 3 over 8, 5 over 6, 5 over 4

3 over 8 and 5 over 6
2 over 9 and 5 over 6
2 over 9 and 5 over 4
3 over 8 and 5 over 4

Answers

the correct answer is 2 over 9 and 5 over 6 

Answer:

2/9 and 5/6

Step-by-step explanation:

divide all the fractions numerator and denominator

and find if the number that is found is repeating

if both fractions are then that is the answer  

Find the first 5 terms of the sequence: an = 4n-1.

Answers

#sol1

a1=1×4-1=3
a2=2×4-1=7
a3=3×4-1=11
a4=4×4-1=15
a5=5×5-1=19

#sol2

f(1)=1×4-1=3,
f(n+1)=f(n)+4,
so .... you know.

The side length of a square ice cube is claimed to be 1.0 inches, correct to within 0.001 inch. Use linear approximation to estimate the resulting error, measured in squared inches, in the surface area of the ice cube.

Answers

Answer:

0.012

Step-by-step explanation:

Linear approximation says that,

f(x) \approx f(x_o)+f'(x_o)(x-x_o)

For a cube the surface area is 6x^2.

So the side is 1.0 inch in, the surface area is =6*1^2 = 6 square inches.  

In Linear approximation means you ignore the term x_o^2 , if x_o is a small number, because then x_o^2 will be a very smalle number and that does not contribute much to the error.  

So the surface area is approximately,

6x^2=6x_o^2+12x_o(x-x_o)

So here, x=1.001, x_o=0.001

The error in the area is approximately,

12 * 0.001=0.012

So the error is 0.012.


Express X^2-8x+5 in the for (x-a)^2-b where a and b are integers

Answers

Answer:

x {}^(2)  - 8x + 5 \n  = x {}^(2) - 8 x+ 5 + 11 - 11 \n  = x {}^(2)   - 8x +16 - 11 \n  = (x - 4) {}^(2)   - 11 \n

A is 4 and b is 11