MATHEMATICS HIGH SCHOOL

A light private plane can fly 120 mph in still air. Flying against the wind, the plane can fly 320 miles in the same time it requires to fly 640 miles with the wind. Find the rate of the wind. A) 120 mph
B) 80 mph
C) 40 mph

Answers

Answer 1
Answer:

Alright, lets get started.

A light private plane can fly 120 mph in still air.

Suppose the speed of wind = x mph

Against the wind, speed of plane will be = 120-x

With the wind, speed of plane will be = 120+x

Flying against the wind, the plane can fly 320 miles, so time taken will be

t = (320)/(120-x)

With the wind, the plane can fly 640 miles, so time taken will be

t = (640)/(120+x)

Both times are given same, so

(320)/(120-x)= (640)/(120+x)

Cross multiplying

320(120+x) = 640(120-x)

Dividing from 320

120+x = 2(120-x)

120+x = 240-2x

3x = 120

x = 40 mph

So, the speed of the wind is 40 mph.  :   Answer

Hope it will help :)
Answer 2
Answer:

Answer:

40

Step-by-step explanation:

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Step-by-step explanation:

the new perimeter is 8 because add all sides

Points points points

Answers

The answer is  A.  informed decisions.
I hope this helps...

Answer:

The answer is A.

Which expression is equivalent to 7a2b + 10a2b2 + 14a2b3?

Answers

The given expression can be simplified in many ways by grouping like terms. The simplest form is obtained by factoring out a²b which gives us the following expression.

a²b(7 + 10b +14b²)

Answer:

a²b(7 + 10b +14b²)

Step-by-step explanation:

7a^2b + 10a^2b^2 + 14a^2b^3

To find out equivalent expression we need to factor the given expression

To factor it first we find out GCF(greatest common factor)

7 a^2b -------> 7*a*a*b

10a^2b^2 ----->5*2 * a*a*b*b

14a^2b^3 -------> 7*2 *a*a*b*b*b

To get GCF we look at the factors that are in common

GCF = a*a*b  that is a^2b

We factor out GCF a^2b, write a^2b outside and divide all the terms by a^2b

a^2b(7 +10b +14b^2)

7+10b+14b^2 cannot be factor . its prime

Which describes the equation: y=4x-51._ the equation has a rate of change of -5 and crosses y intercept at 4
2.- the equation has a rate of change of 4 and crosses y intercept at -5
3._ none of the above
4._ all the above​

Answers

Answer:

hello

Step-by-step explanation:

What are the first three terms of the sequence represented by the recursive formula an=n^2-an-1 if a5=14 1/4

Answers

Answer:

B. 0.25, 3.75, 5.25

just convert what the person above said but into decimals

Answer:

  1/4, 3 3/4, 5 1/4

Step-by-step explanation:

Solving for a[n-1], we get ...

  a[n-1] = n^2 -a[n]

Then ...

  a[4] = 5^2 -a[5] = 25 -14 1/4 = 10 3/4

  a[3] = 4^2 -a[4] = 16 -10 3/4 = 5 1/4

  a[2] = 3^2 -a[3] = 9 -5 1/4 = 3 3/4

  a[1] = 2^2 -a[2] = 4 -3 3/4 = 1/4

Then the first three terms are a[1], a[2], and a[3]:

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The number 248,682 rounded off to the nearest hundreds becomes A. 248,700.
B. 248,680.
C. 249,000.
D. 250,000.

Answers

A. 248,700
_
7 is in the hundreth place.
B. 248,680. 
8 is in the hundredth place, because
6 is the tenth place
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