A number that represents part of a whole or part of the set is called

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Answer 1

Answer: A fraction. Hope this is the correct ans. :)

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In your own words, explain the
term midpoint.

Answers

Ok in my own words hmm.

Midpoint to me would be the point in the middle.

I've seen and worked with midpoints on lines and triangles.

So the midpoint would be the point in the middle of a line segment.

Hope this is helpful!

Answer:

It's the center of a line which involves coordinates (x,y) and by defining a line it's made up of multiple coordinates

Step-by-step explanation:

Hope it's helpful

grant plans to evaporate enough water from 22 gallons of a 16% ammonia solution to make a 24% ammonia solution. Which equation can he use to find n, the number of gallons of water he should remove?

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The equation to get the number of gallons of water he should evaporate
= 22 - (22 x 0.16)/0.24

Write the equation of the line, given the y- and x-intercepts. x-intercept (–6, 0), y-intercept (0, –8)

Answers

neverminding for a second that they're intercepts at all, they're points on the line, so

$\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad(\stackrel{x_2}{0}~,~\stackrel{y_2}{-8})\n\n\n slope = m\implies\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-0}{0-(-6)}\implies \cfrac{-8-0}{0+6}\implies \cfrac{-8}{6}\implies -\cfrac{4}{3}\n\n\n \begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\n\cline{1-1}\ny-y_1=m(x-x_1)\n\n\cline{1-1}\end{array}\implies y-0=-\cfrac{4}{3}[x-(-6)]\n\n\ny=-\cfrac{4}{3}(x+6)\implies y=-\cfrac{4}{3}x-8$

Can you please solve a it is so important

Answers

f(x)=-x2+5n
g(x)=-2n+15
A(x)=|g(x)-f(x)|=|x2-7n+15|
x2-7n+15>0 for every x (1)
A(x)=x2-7n+15

(1):
x2-7n+15=(x-3.5)^2-12.25+15=(x-3.5)^2+2.75 > 0
because for every x: (x-3.5)^2>=0

answer: A(x)=x2-7n+15

Which best describes how to solve this equation for x?
x/a=b

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1. You multiply both sides by a
2. You're done!!!

Please help me on this

Answers

$y+x=8\n y=8-x\n\n (12)/(x)=8-x\qquad x\not=0\n 12=8x-x^2\n x^2-8x+12=0\n x^2-8x+16-4=0\n (x-4)^2=4\n x-4=2 \vee x-4=-2\n x=6 \vee x=2\n\n y=8-6 \vee y=8-2\n y=2 \vee y=6\n \boxed{(x,y)=\{(2,6),(6,2)\}}$

$\displaystyle S_P=\int\limits_2^68-x-(12)/(x)\, dx\n S_P=\left[8x-(x^2)/(2)-12\ln x\right]_2^6\n S_P=8\cdot6-(6^2)/(2)-12\ln 6-(8\cdot2-(2^2)/(2)-12\ln 2)\n S_P=48-18-12\ln 6-16+2+12\ln2\n S_P=16-12\ln 6+12\ln 2\n S_P=16-12(\ln 6-\ln 2)\n\boxed{S_P=16-12\ln 3}$

$\displaystyle S_Q=\int\limits_2^6(12)/(x)\, dx\n S_Q=\left[12\ln x\right]_2^6\n S_Q=12\ln 6-12\ln 2\n S_Q=12(\ln6-\ln 2)\n \boxed{S_Q=12\ln 3}$

$\displaystyle V=\pi \int \limits_a^b f^2(x)\, dx\n\n V=\pi \int \limits_2^6 \left((12)/(x)\right)^2\, dx\n V=\pi \int \limits_2^6 (144)/(x^2)\, dx\n V=\pi\left[-(144)/(x)\right]_2^6\n V=\pi \cdot \left(-(144)/(6)-\left(-(144)/(2)\right)\right)\n V=\pi \cdot (-24+72)\n V=\pi \cdot48\n \boxed{V=48\pi}$

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