What else is produced when sodium carbonate decomposes? Na2CO3 Na2O +

Answers

Answer 1

Answer:

Na2CO3 Na2O +CO2 CO2 is the answer

Answer 2

Answer:

When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.

The chemical symbol for sodium carbonate is $Na_2CO_3$ .

The decomposition of sodium carbonate is:

$Na_2CO_3\rightarrow Na_2O+ CO_2$

The decomposition of sodium bicarbonate, $Na_2CO_3$ will result in the formation of sodium oxide, $Na_2O$ and carbon dioxide, $CO_2$ .

Hence, carbon dioxide, $CO_2$ will produce with sodium oxide, $Na_2O$ on decomposition of $Na_2CO_3$ .

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Which type of radioactive emission has a positive charge and weak penetrating power?(1) alpha particle (3) gamma ray
(2) beta particle (4) neutron

Answers

According to the research, alpha particles are a type of radioactive emission that has a positive charge and weak penetrating power.

What is a alpha particle?

They are very heavy particles that have a positive charge and are composed of two protons and two neutrons from the nucleus of the atom.

That is to say, it is a completely ionized nucleus, without its ideal electron coating, identical to the Helium nucleus and they are of low penetrability.

Therefore, we can conclude that according to the research, alpha particles are a type of radioactive emission that has a positive charge and weak penetrating power.

Learn more about alpha particles here: brainly.com/question/24276675

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1. alpha particle
alpha particles are positively charged helium nuclei with weak penetrating power

5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of HCl 0,1M. What's the % of the inicial mixture?The 14,3mL of HCl are necessary to neutralize the KOH.

What are the reactions and what do I need to calculate?

Answers

we know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572. That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.

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