A cube has a volume of 1/512 cubic meter.What is the length of each side of the cube?Explain your thinking.

Answers

Answer 1
Answer:

The side of the cube will be equal to s = ( 1 / 8).

What is volume?

Volume is defined as the space occupied by any object in the three-Dimensions. All three parameters are required for the volume like length, width and height of cube or cubes.

The volume of a cube is equal to V = s³

Given a volume of 1/512, using the formula.

V = s^3

1/512 = s³

s = ∛1/512

s = 1/8 meter

Therefore the side of the cube will be equal to s = ( 1 / 8).

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Answer 2
Answer: The volume of a cube is equal to V = s^3.
Given a volume of 1/512, using the formula.
V = s^3
1/512 = s^3
s = cuberoot of 1/512
s = 1/8 meter

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What are two equivalent fractions for 2/10, three equivalents fractions for 3/11 and three equivalent fractions for 1/12?

Answers

Well, (2)/(10)=(1)/(5)=(3)/(15)=(4)/(20)=(5)/(25)=(n)/(5n) for every n integer.
(3)/(11)=(6)/(22)=(9)/(33)=(12)/(44)=(15)/(55)=(3n)/(11n) for every n integer.
(1)/(12)=(2)/(24)=(3)/(36)=(4)/(48)=(5)/(60)=(n)/(12n) for every n integer.
2/10 is equal to 1/5 cause u divide by 2 and 4/20 cause u divide by 2.for 3/11 r 6/22 cause multiply by 2 and 9/33 cause u multiply by3 finally 1/12 r 2/24 cause u multiply by 2 and 3/36 cause u multiply by 3

Rewrite using a single positive exponent.
7^4 * 7^-9

Answers

The expression 7^4 * 7^(-9) is equivalent to 1/7^(5).

To rewrite the expression using a single positive exponent, we can use the properties of exponents.

Recall the property of exponents that says a^m * a^n = a^(m + n). This means that when you have the same base raised to different exponents and they are multiplied, you can add the exponents.

7^4 * 7^(-9) = 7^(4 - 9)

Now, simplify the exponent:

7^(4 - 9) = 7^(-5)

Recall another property of exponents that states a^(-n) = 1 / a^n. This means that when you have a negative exponent, you can rewrite it as the reciprocal of the base raised to the positive exponent.

7^(-5) = 1 / 7^5

So, the expression 7^4 * 7^(-9) is equivalent to 1/7^(5).

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7^4 x 7^-9=0.000059
Thats your answer 
i hope it helped you 


At a diner, the cost of a muffin (m) and a cup of tea (t) is $2.10. The cost for two muffins and 3 cups of tea is $5.15. How much does a muffin and a cup of tea cost?

Answers

Answer:

ok so one muffin and one cup of teat cost $2.10 ok now I did guess and check and I got one muffin cost $1.15 and one cup of tea is $.95

1.15*2=2.30

.95*3=2.85

2.30+2.85=5.15

Step-by-step explanation:

Answer: ok so one muffin and one cup of teat cost $2.10 ok now I did guess and check and I got one muffin cost $1.15 and one cup of tea is $.95

Step-by-step explanation:

$.95

1.15*2=2.30

.95*3=2.85

2.30+2.85=5.15

What is the range of 50,48, 56, 58, 54, 50, 48, 56, 46

Answers

 you have to take 58-46= 12
The range is... 12.

subtract the highest value from the lowest value 

58 - 46 = 12

Which expressions are equivalent to -3-(7.5+4)

Answers

-3-(7.5+4)
PEMDAS
P for Parenthesis
E for Exponents
M/D for Multiplication/Division
A/S for Addition/Subtraction
We should first clear the ones in parenthesis: (Oder Of Operations)
= -3-(11.5)
= -3-11.5
= -14.5
Basically -3-(11.5)

Aldrin and Jan are standing at the edge of a huge field. At 2:00 p.m., Aldrin begins to walk along a straight path at a speed of 3 km/h. Two hours later, Jan takes a straight path at a 608 angle to Aldrin’s path, walking at 5 km/h. At what time the two friends be 13km apart?

Answers

Answer: After 2:29 hours both Aldrin and Jan will be 13 km apart from each other.

Time at that instant will be : 4:00 pm + 2.29 hours= 6:29 pm

Step-by-step explanation:

According to the figure:

Ab= c = 13 Km

AC = b = distance= speed* time =5* t=5t Km

After two hours the distance covered by the Aldrin say till point D :

distance=speed* time=3km/hr* 2 hrs=6 Km

Since, we are interested in determining the time at which Aldrin and Jan both 13 Km apart. For that Aldrin Additional distance covered by the Aldrin from point D to B is :

distance=speed* time= 3km/hr* t=3t Km

CB= a = CD+DB= 6+3t

We will apply Laws of cosines:

C^2=A^2+B^2-2AB* Cos\theta

(13)^2=(6+3t)^2+(5t)^2-2(5t)(6+3t)Cos 60^o

19t^2+6t-133=0

On solving the the above equation by quadratic formula we get two values of 't'

1) t = 2.49 hours , 2) t = -2.80 hours

Since,time cannot be in negative so we will ignore the negative value of t

t = 2.49 = 2:29 hours ,(0.49 hour=0.49 × 60 min=29.4 min)

After 2.49 hours after the walking of Jan. Both Aldrin and Jan will be 13 km apart from each other.

Time at that instant will be : 4:00 pm + 2:29 hours= 6:29 hour