Julio walks 3/1/2 miles in 1/1/4 hours
Answers
2.8 is your answer...
Hope this helps...
You dint state your question
Related Questions
Write a word problem for the equation: 1/2 x 2/3 = X
Three geometric sequences are given below. Sequence A: 160,40,10,2.5,...Sequence B: -21,63,-189,567,...Sequence C: 8,12,18,27,....Order the sequences from least common ratio to the greatest common ratio.
Could someone help me finding out the missing answers?
Is there a number that it’s absolute value plus one is equal to -2?
Answers
23 1/4 * 3 = 69 3/4
joans sister walked 3 times farther.
Answers
Answer:
The answer should be a.) $5 per mile
hopefully my answer helps! ♡
(if my answers helped you please tell me, therefore I know.. that I did them correctly or incorrectly. anyways, have a great day/night!)
Step-by-step explanation:
it's a, because it mentions the rate of change, which is increasing... meaning it's a positive rate of change.
Answer:
The answer is A
Step-by-step explanation:
As every mile goes by 5$ is added to the meter, so in six miles with a starting meter of 3 for the ride is 33$
Your Welcome! :)
B.) which town had the greater percent in increase?
Answers
Firstly the population of town A increses from 1346 to 1500
Then the total increase in population of town A = 1500 - 1346
= 154
Percentage of increase in population of town A = (154/1346) * 100
= 11.44
So the population of town A increases by 11.44%
Secondly the population of town B increases from 1546 to 1800
Then the total increase in population of town B = 1800 - 1546
= 254
Percentage increase in population of town B = (254/1546) * 100
= 16.42
So the population of town B increases by 16.42%
Also town B had the greater percentage increase in population.
Answers
A.
y+5>-2
y>-7
C.
y+5<-2
y<-7
The one with greater than is A so that is your answer.
OL
⊥
ON
start overline, O, L, end overline, \perp, start overline, O, N, end overline
\qquad m \angle LOM = 3x - 15^\circm∠LOM=3x−15
∘
m, angle, L, O, M, equals, 3, x, minus, 15, degrees
\qquad m \angle MON = 5x - 23^\circm∠MON=5x−23
∘
m, angle, M, O, N, equals, 5, x, minus, 23, degrees
Find m\angle MONm∠MONm, angle, M, O, N:
Answers
Segments LO and ON are perpendicular, providing the required
information for the value of the sum of ∠LOM and ∠MON.
- m∠MON is 57°
Reasons:
The given parameter are;
is perpendicular to
;
m∠LOM = (3·x - 15°)
m∠MON = (5·x - 23°)
Required:
Find m∠MOM
Solution:
Given that is perpendicular to
, we have;
m∠LON = 90° by definition of perpendicular lines
m∠LON = m∠LOM + m∠MON by angle addition postulate
Therefore;
m∠LOM + m∠MON = 90° by substitution property of equality
Which gives;
(3·x - 15°) + (5·x - 23°) = 90° by substitution property
8·x - 38° = 90°
x = 16°
m∠MON = 5·x - 23°
m∠MON = 5 × 16° - 23° = 57°
- m∠MON = 57°
Learn more here:
Answer:57
Step-by-step explanation:
Answers
Answer:
B
Step-by-step explanation:
sorry!