How can you use addition and subtract to put together and separate measures of an angle and its parts

Answers

Answer 1

Answer: How can you use addition and subtract to put together and separate measures of an angle and its parts

Adding and Subtracting angles can be put this way.
Complementary angles can be formed by two angles with total of 90 degrees.
Supplementary angles can be formed by two angles with total of 180 degrees.

X + Y = 90 degrees
Y = 90 - X
X = 90 - Y

X + Y = 180 degrees
Y = 180 - X
X = 180 - Y

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Write the expression as the sine, cosine, or tangent of an angle. sin 57° cos 13° - cos 57° sin 13°
Select one:
a. cos 70°
b. cos 44°
c. sin 44°
d. sin 70°

Answers

Answer: The correct option is (c) sin 44°.

Step-by-step explanation: We are given to write the following expression as the sine, cosine or tangent of an angle :

$T=\sin 57^\circ\cos13^\circ-\cos57^\circ\sin13^\circ.$

We will be using the following trigonometric formula :

$\sin (A+B)=\sin A\cos B-\cos A\sin B.$

Therefore, we get

$T\n\n=\sin 57^\circ\cos13^\circ-\cos57^\circ\sin13^\circ\n\n=\sin(57^\circ-13^\circ)\n\n=\sin 44^\circ.$

Thus, the required expression can be written in sine of an angle of measure 44°.

Option (c) is CORRECT.

Use this formula: sin (x-y) = sinx cosy - cosx siny

sin57 cos13 - cos57 sin13 = sin (57 -13) = sin (44)

-5v-6=3v+10 i really hate math but i need help

Answers

OK. We could have gotten along nicely without the comment.

-5v - 6 = 3v + 10

I think what you're trying to find is the number that ' v ' must be
in order to make the equation a true statement. That number
is called the 'solution' of the equation.

To find it, you have to massage and manipulate the equation around
until you have ' v ' and nothing else on one side. You can do anything
you want to a whole side of the equation, but whatever you do to one
side, you must immediately do to the other side. Here's one way you
could go about it:

-5v - 6 = 3v + 10

Add 5v to each side: -6 = 8v + 10

Subtract 10 from each side: -16 = 8v

Divide each side by 8 : -2 = v

Now, was that so painful ?

3. Irvin cut a 47 in. wire into two pieces. The longer piece is 13 in. longer than the shorter piece. What is the length of the longer piece?_________ in.

Please Help!!!

Answers

Let's say x to the shoter piece's length, since the longer one is 13 in longer, it's length has to be x+13 in. We know the sum of these pieces is equal to 47. So let's solve:
$x+x+13=47\n 2x+13=47\n 2x=47-13\n 2x=34\n x=\frac { 34 }{ 2 } \n x=17$
the shorter piece's length 'x' is 17 , so the longer piece's length 'x+13' is : $x+13\n 17+13=30$

Answer:

30 inches.

Step-by-step explanation:

i took the test and got it correct.

Consider f(x)=2|x|What is the rate of change over the interval 0≤x≤4?

How is the rate of change over this interval related to the form of the function?

Answers

Answer:

Please check the explanation.

Step-by-step explanation:

As we know that the average rate of change of f(x) in the closed

interval [a, b] is

$(f\left(b\right)-f\left(a\right))/(b-a)$

Given the interval [a, b] = [0, 4]

$f(x)=2|x|$

$f(b)=f(2)=2\cdot \:4$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$= 8$

$f(x)=2|x|$

$f(a)=f(0)=2\cdot \:0$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$= 0$

so the average rate of change :

$(f\left(b\right)-f\left(a\right))/(b-a)=(8-0)/(4-0)$

$=(8)/(4)$

$= 2$

We know that a rate of change basically indicates how an output quantity changes relative to the change in the input quantity. Here, it is clear the value of y increase with the increase of input.

Line WY is a Tangent. Find WY. It's a right triangle inside a circle..any help?

Answers

For this question, you can do Pythagorean Theorem to solve WY. Since WY is tangent to the circle, we know that the triangle is a right triangle.

We know one leg is 9 and the other leg, WY is unknown. But, we do know the hypotenuse.

XY is 6 but PX is unknown. If you think about it, PX is a radius of the circle and we know that the radius is 9 since PW is also a radius of the circle. So, the hypotenuse is 6 + 9 = 15.

We know one leg is 9 and the hypotenuse is 15. We need to find the other leg and we can.

Pythagorean Theorem states that

a^2 + b^2 = c^2 where a and b are the sides of the triangle and where c is the hypotenuse. Using basic algebra, we can alter the equation to find a leg using the hypotenuse and one other leg.

c^2 - b^2 = a^2

All I did was solve for one leg and it doesn't matter what leg you solve for. Let's plug in the numbers.

15^2 - 9^2 = a^2
225 - 81 = a^2
144 = a^2
Take the square root on both sides to get "a" by itself with raising it to the second power.

12 = a

So, the last leg is 12. Hope this helped and good luck!

I don't have answer for this but I m seeing you not answering a lot of stuff,you should start lessening :)

What does the product of any whole-number factor multiplied by 100 always have ? Explain

Answers

The product of any whole number factor multiplied by 100 basically is just the number with an extra two zeros on the end. This is the case with any whole number.

Examples:
13 x 100 = 1300
444 x 100 = 44400
7 x 100 = 700

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