MATHEMATICS HIGH SCHOOL

Solve the system of equations.2x + 3y = 13
–6x + 4y = 0
A.
(2, 3)
B.

C.
(5, 1)
D.
(–2, –3)
Solve the system of equations. 2x + 3y = 13 - 1

Answers

Answer 1
Answer:

2x + 3y = 13

–6x + 4y = 0

multiply the first equation by 3

6x +9y = 39

then add the 2nd equation to the first

6x +9y = 39

–6x + 4y = 0

-------------------

13y = 39

divide by 13

y =3

now take an equation and solve for x by substituting in y

2x +3y =13

2x +3(3) =13

2x+9 =13

subtract 9 from each side

2x =4

divide by 2

x=2

Answer (2,3)

Choice A
Answer 2
Answer:

Answer:

a

Step-by-step explanation:

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