mr. pollack's biology class observed the growth of pea plants. if 5 pea plants grew to 30 cm and 15 pea plants grew to 50 cm, what was the overall average height of the pea plants

Answers

Answer 1

Answer: u do 5 times 30 and get 150 then take 15 times 50 and get 750 last take 750 plus 150 and u get 900 cm

Answer 2

Answer:

Final answer:

To find the overall average height of the pea plants, we need to calculate the total height and divide it by the total number of plants. The overall average height of the pea plants is 45 cm.

Explanation:

To find the overall average height of the pea plants, we need to calculate the total height of all the plants and divide it by the total number of plants. Let's calculate:

The total height of the 5 plants that grew to 30 cm is 5 multiplied by 30, which equals 150 cm.
The total height of the 15 plants that grew to 50 cm is 15 multiplied by 50, which equals 750 cm.
The overall total height of all the plants is 150 cm + 750 cm, which equals 900 cm.
The overall average height of the pea plants is 900 cm divided by the total number of plants, which is 5 + 15 = 20 plants. So, the overall average height is 900 cm divided by 20, which equals 45 cm.

Therefore, the overall average height of the pea plants is 45 cm.

Learn more about Average Height of Pea Plants here:

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1. Solve through substitution
y = -3.x + 4. y = 4x – 10
Enter your math answer

Answers

Answer:

y= -2 and x= 2.

Step-by-step explanation:

(y=-3x+4)4

(y=4x-10)3

make the x's cancel out.

you get 7y=-14.

y=-2.

-2=-3x+4

x=2

Solve the equation for y. 8x – 9y = 11a. .y=-9/8x-9/11
b. .y=9/8x 11/8
c. .y=-8x-11
d. .y=8/9x-11/9

Answers

8x - 9y = 11 (subtract 8x from each side)

- 9y = -8x + 11 (divide -9 from each side)

$(-9y)/(-9) = (-8x+11)/(-9)$

y = $(-8)/(-9) x - (11)/(9)$

D. $y=(8)/(9) x - (11)/(9)$

Using the U- Substitution u=sqrt(2x), integral form 2-8 dx/ sqrt(2x) + 1 is equivalent to ...I'm not quite sure how to solve using u substitution.

Help please!

Answers

We will use u-substitute: $u= √(2x) , (du)/(dx)= (1)/( √(2x) )= (1)/(u)$ Then for substitution:dx=u du. and integral becomes: $\int { (u)/(u+1) } \, du = \int { (u+1-1)/(u+1) } \, du= \int{1} \, du- \int { (1)/(u-1) } \, dx$ =u-ln(u+1)= $√(2x)-ln( √(2x)+1)$ . Now we will change the values of limits: $√(16)-ln( √(16)+1)-( √(4)-ln( √(4)+1))$ =4-ln(5)-2+ln(3)=2+ln(0,6)=2-0.51=1.49

(−6)^2
Need halp please

Answers

This is an EXPONENT.

To do this all we need to do is multiply the base by itself how many times the power says.

(-6)² = (-6) × (-6) = 36

Recall that any negative number times another negative number is positive so that is why this would be positive.

So, (-6)² = 36

Hope I helped ya!!

(-6) x (-6) = **36**

What is the value of x?
Enter your answer in the box

Answers

Answer:

could we have a picture or the equation?? plz

Answer:

is there any more to the question??

Can anyone please help with this question

Answers

so 4(x+5)=x+8
first we distribute
using the distributive property of multiplication which is a(b+c)=(ab)+(ac)

4(x+5) is also (4x)+(4(5))=4x+20

4x+20=x+8
subtract x from both sides
3x+20=8
subtract 20 from both sides
3x=-12
divide both sides by 3
x=-4

4(x+5)=x+8
4x+4*5=x+8
4x+20=x+8
4x-x+20=x+8-x
3x+20-20=8-20
3x=-12
3x/3=(-12)/3
x=-4

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