Tom predicted that the Giants would score three 3-point field goals, score two 6-point touchdowns, and score 1 extra point. If Tom were correct, what would the Giants' score be at the end of the game?
Answers
2*6 = 12
1*1 = 1
9+12+1 = 22
The Giants would score 22 points if Tom is correct
three 3-point field goals = 3×3= 9
two 6-point touchdowns = 2×6=12
score of 1 extra point=1
Now add all the answers together...
9+12+1=22
HOPE THIS HELPED :)
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What is the least common multiple (LCM) of 4 and 10?
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Answer:
the triangle with 15 mini-squares
Answers
Answers
Answer:
3/50
Step-by-step explanation:
P( 1st ball is a black ball) = number of black balls/ total balls
= 2/10 = 1/5
We put the ball back so we still have the same number of balls
P( 2nd ball is a red ball) = number of red balls/ total balls
= 3/10
P (1st ball black, 2nd red) = P( 1st ball is a black ball)* P( 2nd ball is a red ball)
=1/5* 3/10
= 3/50
Answers
I hope this helps. Enjoy the rest of you day :)))
Answer:
3x + 3
Step-by-step explanation:
(2x - 2) + (x + 5)
Combine like terms:
2x + -2 + x + 5
(2x + x) + (-2 + 5)
3x + 3
Hope you learned from this answer!
Answers
Answer:
Area of the sector(A) is given by:
where,
r is the radius of the circle and is the central angle in degree.
As per the statement:
The area of the sector formed by the 110 degree central angle is 50 units squared.
⇒A = 50 units squared and
Substitute these in [1] and use 3.14 for pi we have;
⇒
Divide both sides by 0.959444446 we get;
⇒
Simplify:
r ≈ 7.22 units
Therefore, the radius of this circle is, 7.22 units
Let make a rule of three.
For 360° area of the circle is π R²
For 1° ............of the sector .. πR²/360
For 110° ............................... πR²*110/360 =50(units squared)
R²=50*360/(110π)
==>R=6*√(50/(11π))≈7,217137....(units)
6z−10w=8
Answers
Answer:
if your looking for z it is 5/8k+2.375
Step-by-step explanation:
Answer:
Step-by-step explanation:
Please, include the instructions.
I'm assuming you want to solve this system of linear equations for z and w, assuming that k is an unknown constant.
Use the method of elimination by addition and subtraction. To eiiminate w, multiply all four terms of the first equation by 10, obtaining:
10 z + 10w - 30 = 10k
6z - 10 w = 80
Then 16z - 30 - 80 = 10k, or
16z -110 = 10k, Simplifying this, we get:
10(k + 11)
z = ---------------
16
Substituting this expression for z into the first equation, we get:
(10/16)(k + 11) + w - 3 = k. We must solve this for w:
-(10/16)(k + 11) + w - 3 = k), or
-(10/16)(k + 11) - w + 3 = -k
Then -(10/16)(k + 11) + 3 + k = w
and so the solution, in terms of the unknown constant k, is
10(k + 11)
( --------------, -(10/16)(k + 11) + 3 + k )
16