If the bug has a mass of 0.05 kg and accelerates at 2 m/s2 whats the net force on the bug

Answers

Answer 1
Answer: Force = (mass) x (acceleration) = (0.05 kg) x (2 m/s²) = 0.1 Newton.

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suppose a vacuum cleaner use 120 j of electrical energy. If 45 j are used to pull air into the vacuum cleaner, how efficient is the vacuum cleaner?

Answers

It depends on how much time 45 j will go, so if you told me that it went through 45 j per minute it will go through for 2 minutes so not efficient unless it went through 45 j per hour then it is efficient. 

Final answer:

The vacuum cleaner's efficiency is calculated as 37.5%. This is determined by the ratio of useful energy output (45J) to total energy input (120J). Real-world devices typically have efficiencies less than 100% due to energy losses.

Explanation:

The vacuum cleaner's efficiency can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) x 100%. In this scenario, the vacuum cleaner used a total of 120 joules of electrical energy, but only 45 joules of that energy were used for the useful task of pulling in air. Therefore, the vacuum cleaner's efficiency would be calculated as: Efficiency = (45 J / 120 J) x 100% = 37.5%.

It's important to understand that real machines do not achieve 100% efficiency because some energy is always lost as heat due to friction and air resistance. As such, the vacuum cleaner's efficiency of 37.5% fits within expected bounds for real-world devices.

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The displacement vector from your house to the library is 760 m long, pointing 35° north of east. What are the components of this displacementvector?

Answers

Answer:

The two components of displacement vector are:

East:760\cos 35=622.56\ m\nNorth:760\sin 35=435.92\ m

Explanation:

Given:

The magnitude of displacement is 760 m.

The direction of the displacement vector is 35° North of East.

North of East means that the vector is between North and East and makes an angle of 35° with the east direction.

Now, there are two components of this displacement vector. One component is along the East direction and the other perpendicular to the East direction which is the North direction.

Component along the East direction is given as:

East:760\cos 35=622.56\ m

Component along the North direction is given as:

North:760\sin 35=435.92\ m

Therefore, the two components that are mutually perpendicular to each other are 622.56 m East and 435.92 m North.

Final answer:

In physics, the vector components of a displacement of 760 meters at an angle of 35 degrees north of east are approximately 622 meters eastward and 435 meters northward.

Explanation:

The displacement vector you're describing is associated with a movement that falls under the umbrella of vector algebra, a common topic in physics. We're given a magnitude (760 m) for the vector and a direction (35° north of east).

We decompose, or break down, this displacement vector into its component along the east (x-direction) and north (y-direction). This splitting of vectors into components is useful when dealing with multiple vectors as it simplifies calculations.

For the eastward component (x-component, or horizontal), we use the cosine of the given angle. For the Northward component (y-component, or vertical), we use the sine of the given angle. The formulas are as follows:

  • Eastward component=x = 760 m * cos(35)
  • Northward component=y = 760 m * sin(35)

Calculating these gives us roughly x = 622 m eastward and y = 435 m northward. These are the vector components of your original displacement vector.

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How are forces able to act at a distance ?

Answers

Magnetic forces act at a distance. The opposites attract and pull each other closer

Which term refers to the bending of light rays when they encounter the edge of a barrier?A
interference

B
reflection

C
refraction

D
diffraction

Answers

Answer: Refracrion

Explanation: it is the bending of light

Your shopping cart has a mass of 65 kilograms, In order to accelerate the shopping cart down an aisle at 0.3 m/sec2, what force would you need to use or apply to the cart?

Answers

remember Newton's second law: F=ma

to get the force in newtons, mass should be in kg and acceleration in m/s^2

conveniently, we don't need to convert units

we just need to multiply the two to get the force

65* 0.3 = 19.5 kg m/s^2 or N

if significant digit is an issue, the least number if sig figs is 1 so the answer would be 20 N

Final answer:

To accelerate a shopping cart with a mass of 65kg at a rate of 0.3 m/sec2, you would need to exert a force of 19.5 Newtons, according to Newton's second law of motion.

Explanation:

The subject of this problem is physics, specifically the concept of force, mass, and acceleration within the domain of Newton's second law of motion. The law states that the force needed to accelerate an object is equal to the mass of the object multiplied by the desired acceleration.

Given the mass of the cart is 65 kilograms and the acceleration is 0.3 m/sec2, you can calculate the required force using the formula:
Force = mass * acceleration.

So, Force = 65 kg * 0.3 m/sec2 = 19.5 Newtons. Therefore, you would have to exert a force of 19.5 Newtons to accelerate the shopping cart at the specified rate.

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If two automobiles have the same velocity, do they have the same acceleration?

Answers

Not at all.

Examples:

-- They could be on the same road, driving in the same direction.
Still, one may be slowing down while the other one is speeding up.
Then, their accelerations have opposite signs, and may have different
magnitudes, but there may very well be an instant when their velocities
are equal.

-- They may both have the same steady speed, but one is on a straight
road while the other one is on a circular track.  At the instant when both
are facing in the same direction, their velocities are equal, although the
first one has no acceleration at all and the second one has a constant
centripetal acceleration.