A sample of water and alcohol are mixed. What method should be used to separate them? -Screening -Filtering -Fractional distillation -density
Answers
Answer;
Fractional distillation
Explanation;
-Fractional distillation is one of the method that is used to separate mixtures. It is used for the separation of miscible liquids, for example water and alcohol.
-Fractional distillation is a distillation method that is used to separate liquids that dissolve in each other. It involves separating the components of a mixture by repeated distillations and condensations.
-The components in the mixture being separated by this method normally have different but close boiling points. For example a mixture of alcohol and water, they have different but close boiling points, thus during distillation alcohol condenses out as the first fraction followed by water.
Related Questions
Is it possible for an object not to be in motion and still have force acting upon it?
Olive oil has a density of 0.92 g/mL. How much would 1 liter of olive oil weigh in grams?
Write the net ionic equation for the following reaction: AgC2H3O2(aq) + CaCl2(aq) →
If a reaction system has come to equilibrium, the concentration of products can be increaseda. only if it is not reversible. c. by applying Le Châtelier’s principle. b. only if the temperature is low enough. d. under no circumstances.
(2) Add 30. g of solute to 970. mL of solvent to make 1.0 L of solution.
(3) Add 1000. g of solvent to 30. g of solute.
(4) Add enough solvent to 30. g of solute to make 1.0 L of solution.
Answers
A student wants to prepare a 1.0-liter solution of a specific Molarity. The student determines that the mass of the solute needs to be 30. grams. Add enough solvent to 30. g of solute to make 1.0 L of solution.
What is molarity ?
The proportion of solute moles to solution length is known as molarity. By dividing the number of moles of HCl by the volume (L) of the solution in which it was dissolved, we may get the acid solution's molarity.
A chemical species' concentration in a solution, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration.
A mole is a unit of measurement for a chemical substance, and it is from this unit that the word "molarity" is derived. The method of figuring out how much of a material a certain chemical solution contains is known as molecularity, sometimes known as the molar concentration of a solution.
Thus, option 4 is correct.
To learn more about molarity, follow the link;
#SPJ2
Answers
Considering the definition of molar mass and molarity, the volume of each compound is:
- NaCl= 0.1355 L
- C₂H₆O = 0.0622 L
- CH₃COOH = 0.047 L
Definition of molar mass
The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
Definition of molarity
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
Molarity is expressed in units.
Volume required
You know that the molar mass of each compound is:
- NaCl = 58.44 g/mol
- C₂H₆O = 46.06 g/mol
- CH₃COOH = 60.0 g/mol
On the other side, you know that the mass of each compound is:
- NaCl = 2.14 g
- C₂H₆O = 4.30 g
- CH₃COOH = 0.85 g
Then, considering the definition of molar mass, the amount of moles of each compound is:
- NaCl =
= 0.0366 moles
- C₂H₆O =
= 0.0933 moles
- CH₃COOH =
= 0.0141 moles
The molarity of each compound is:
- NaCl = 0.27 M
- C₂H₆O = 1.50 M
- CH₃COOH = 0.30 M
Considering the molarity, the volume of each compound is calculated as:
- NaCl =
= 0.1355 L
- C₂H₆O =
= 0.0622 L
- CH₃COOH =
= 0.047 L
Learn more about
molar mass:
molarity:
number of moles : 2.14 / 58.44 = 0.0366 moles
V = n / M => 0.0366 / 0.270 = 0.1355 L
__________________________________________
b) C2H6O = 46.06 g/mol
number of moles : 4.30 / 46.06 = 0.0933 moles
V = n / M => 0.0933 / 1.50 = 0.0622 L
___________________________________________
c) CH3COOH = 60.0 g/mol
number of moles : 0.85 / 60.0= 0.0141 moles
V = n / M => 0.0141 / 0.30 = 0.047 L
___________________________________________
hope this helps!
Answers
The errors could root from:
-measurement of the thickness incosistently (at different times of the day)
-the instrument used is different in each measurement
-no regard of significant figures
-standard deviation from the mean is not calculated and not propagated
Answers
Answers
Answer:
b.
utilizing facts
Explanation: