Recall Elmer Trett, who in 1994 reached a speed of 103m/s on his motorcycle. Suppose trett drives off a horizontal ramp at this velocity and lands a horizontal distance of 40.0m away from the edge of the ramp. What is the height of ramp?
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Speed of the motor cycle is given as
distance that he moved off from the ramp is given as
now we know that
now we can use this to find the height
so its height will be 75 cm from ground
Final answer:
The height of the ramp is approximately 0.748m.
Explanation:
To find the height of the ramp, we can use the equations of motion. Since the motorcycle leaves the ramp horizontally, the horizontal distance traveled is equal to the initial horizontal velocity multiplied by the time of flight.
Using the equation x = vt, where x is the horizontal distance traveled, v is the initial horizontal velocity, and t is the time of flight, we can solve for t.
For this problem, the horizontal distance is 40.0m and the initial horizontal velocity is 103m/s. Substituting these values into the equation, we get t = x/v = 40.0m / 103m/s = 0.388s.
Next, to find the height of the ramp, we can use the equation h = (1/2)gt^2, where h is the height of the ramp and g is the acceleration due to gravity (approximately 9.8m/s^2). Substituting the value of t we found into the equation, we get h = (1/2)(9.8m/s^2)(0.388s)^2 = 0.748m.
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