a stream flows with a speed of 3.0 meters per second relative to the shore. A kayaker paddles Downstream with the speed of 1.5 meters per second relative to the stream. What is the kayaker speed relative to the shore

Answers

Answer 1
Answer:

Since the kayakers speed is 1.5 meters per second relative to the stream, the kayakers velocity in meters per second relative to the shore should be its speed relative to the stream plus the stream's velocity relative to the shore. This is 1.5m/s + 3.0m/s which is equal to 4.5 meters per second (m/s).

Answer 2
Answer:

Final answer:

The kayaker's speed relative to the shore is calculated by adding the stream's speed (3.0 m/s) and the kayaker's speed relative to the stream (1.5 m/s), which results in 4.5 m/s.

Explanation:

In this scenario, the kayaker's total velocity, or speed relative to the shore, is the vector sum of the kayak's velocity relative to the water and the water's velocity relative to the shore. This principle reflects how velocities combine in Newtonian mechanics. Given that the stream's velocity is 3.0 meters per second and the kayaker's velocity relative to the stream is 1.5 meters per second, we add these velocities together to get the kayaker's velocity relative to the shore.

Therefore, the kayaker's speed relative to the shore is 4.5 meters per second. This sum is based on the principle that when moving downstream, the stream's velocity (its speed in a particular direction) augments the velocity of the kayak.

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Answers

6.

Answer:

45 meters

Explanation:

notice that is you multiply the time with the speed the units cancel to get distance.

therefore

distance=velocity(time)

distance=(3)15

distance =45 meters

7.

Answer:

1. the speed is constant

2. the average speed is .5 m/s

Explanation:

I have attached a graph of the data in excel.

from excel i got the equation of the line to be y=.5x with y being distance and x being time.

the function is a position function so if you take the derivative of it you get the velocity which is .5.

since the derivative is a constant the the speed does not change and the average velocity is the derivative.

What would happen to the amount of matter on earth if mass were not conserved during changes of state?

Answers

earth would be thrown off its balance and nature would be in danger of too many resources and not enough resources 
it would be very bad earth wouldve felled

Which of the following is determined by local government?Select one:
A. zoning laws
B. immigration reforms
C. international treaties
D. the amount of money in circulation

Answers

Answer:

B

Explanation:

b
zzzzzzzzzzzzzzzzzz

A teacher points to a microscope sitting on the desk. Which conclusion best explainswhy the microscope is not moving?

Answers

Answer:

The object is sitting

Explanation:

Therefore the object cannot be in current motion as no force has been acted upon it (exept gravitational force)

The gravitational attraction between two objects will ________if one object acquires more mass

Answers


The gravitational force between two objects is proportional to the
product of their two masses.  So if either object acquires more mass,
the magnitude of the gravitational attraction between them increases.

Here is a translation of the same statement, into simple English:

If you are on Earth, and your mass increases because you ate a lot,
then your weight will increase.  

· A hot, just-minted copper coin is placed in 101 g of water to cool. The watertemperature changes by 8.39°C, and the temperature of the coin changes
by 68.0°C. What is the mass of the coin?
Please helppp!!!

Answers

The mass of the copper coin placed in 101g of water is 135.3g.

COLORIMETER:

The mass of the copper coin can be calculated using the following expression:

Since; Q = mc∆T

Where;

  • Q = heat absorbed or released
  • m = mass of substance
  • c = specific heat capacity of substance
  • ∆T = change in temperature
  • mc∆T (water) = mc∆T (copper)

According to the question;

COPPER METAL:

  • m = ?
  • c = 0.385 J/g°C
  • ∆T = 68°C

WATER:

m = 101g

c = 4.18 J/g°C

∆T = 8.39°C

⇒ 101 × 4.18 × 8.39 = (0.385 × m × 68)

⇒ 3542.09 = 26.18m

⇒ m = 3542.09 ÷ 26.18

m = 135.3g

Therefore, the mass of the copper coin placed in 101g of water is 135.3g.

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Answer:

135g

Explanation: