Describe three possible ways in which a hypothesis may arise

Answers

Answer 1

Answer: 1- By forming evidence.

This is when evidence and statistics are formed and found and can help form a hypothesis.

2- Multiple attempts

This is when multiple attempts form the same product

3- Enough research

Research is shown and enough to prove something.

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Of all boron atoms, 19.9%% are boron-10, which have a mass of 10.01294 amu. The other 80.1% of boron atoms are boron-11 and these have a mass of 11.00931. Calculate the average atomic mass of boron.

Answers

Answer:

10.81 amu

Explanation:

The average atomic mass of Boron can be calculated as follows :

$A=19.9\%\ \text{of}\ 10.01294 +80.1\%\ \text{of}\ 11.00931\n\nA=(19.9)/(100)* 10.01294 +(80.1)/(100)* 11.00931\n\nA=10.81\ \text{amu}$

So, the average atomic mass of boron is 10.81 amu.

eleanor wants to show her class a comparison of melting rates between two different solids when he is applied why would a graph be more suitable than a table to show her data

Answers

Eleanor wants to show her class a comparison of melting rates between two different solids when heat is applied. A graph would be more suitable than a table to show her data because the she can see the trend line of the effects of melting than the table.

Jello has a density of 1.14 g/mL. A box of Jello makes 475 mL of Jello and has 13 g of sugar. Determine the % m/m of sugar in the Jello. (Hint: d=m/v)

Answers

Answer:

2.34 %

Explanation:

Since the density of the Jello, ρ = 1.14 g/mL and ρ = m/v where m = mass of jello and v = volume of jello = 475 mL.

So, m = ρv

substituting the values of the variables into the equation, we have

m = ρv

m = 1.14 g/mL × 475 mL = 541.5 g

Since we have 13 g of sugar in the jello, the total mass present is 13 g + 541.5 g = 554.5 g

So, the percentage by mass of sugar present % m/m = mass of sugar present/total mass × 100 %

= 13 g/554.5 g × 100 %

= 0.0234 × 100 %

= 2.34 %

So, the percentage by mass of sugar present % m/m = 2.34 %

A faster pulse rate results in a _____ overall heat input. Answer options are 1. Higher or 2. Lower

Answers

a faster pulse rate results in a higher overall heat input

Answer:

higher

Explana

In which compound is the percent compositionby mass of chlorine equal to 42%?(1) HClO (gram-formula mass = 52 g/mol)
(2) HClO2 (gram-formula mass = 68 g/mol)
(3) HClO3 (gram-formula mass = 84 g/mol)
(4) HClO4 (gram-formula mass = 100. g/mol)

Answers

The percentage mass composition of chlorine in HClO₃ is 42%.

What is the percentage mass composition of chlorine in each compound?

Percentage mas of chlorine is calculated as follows:

Percentage mass composition = mass of element * 100%/mass of compound

atomic mass of chlorine = 35.5

(1) In HClO (gram-formula mass = 52 g/mol)

Percentage mass composition = 35 * 100% / 52 = 67.3%

(2) In HClO2 (gram-formula mass = 68 g/mol)

Percentage mass composition = 35 * 100%/68 = 51.4%

(3) HClO3 (gram-formula mass = 84 g/mol)

Percentage mass composition = 35 * 100% / 84 = 42%

(4) HClO4 (gram-formula mass = 100. g/mol)

Percentage mass composition = 35 * 100% / 100 = 35.5%

Therefore, the percentage mass composition of chlorine in HClO₃ is 42%.

Learn more about percentage mass composition at: brainly.com/question/18646836

Final answer:

None of the compounds have a percent composition of chlorine equal to 42%.

Explanation:

To find the compound with a percent composition of chlorine equal to 42%, we calculate the mass of chlorine in each compound and calculate the percent composition. Let's go through each option:

HClO: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (35.5/52) * 100% ≈ 68.3%. Not equal to 42%
HClO2: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (2 * 35.5/68) * 100% ≈ 104.4%. Not equal to 42%.
HClO3: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (3 * 35.5/84) * 100% ≈ 150%. Not equal to 42%.
HClO4: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (4 * 35.5/100) * 100% = 142%. Not equal to 42%.

None of the compounds have a percent composition of chlorine equal to 42%. The correct answer is none of the above.

Learn more about Percent composition of chlorine here:

brainly.com/question/2529200

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mixture or pure substance: 1.blood 2.dyes 3.self-raising flour 4.muesli 5.copper wire 6.distilled water 7.table salt 8.milk 9.bronze 10.tea 11.oxygen 12.air

Answers

Answer: Mixture: Blood , Self raising flour,muesli ,dyes, milk, tea, air, bronze

Pure substance: Copper wire, distilled water, table salt, oxygen.

Explanation:

Mixture is a substance which is made up two or more number of compounds which chemically inactive and retain their distinct chemical properties.

Blood , Self raising flour,muesli ,dyes, milk, tea, air, bronze

Pure substance is defined as anything with uniform and unchanging composition is known s pure substance.

Copper wire, distilled water, table salt, oxygen.

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