the length of a rectangle is 5 less than 3 times the width. the perimeter is 150 centimeters. what is the length and width?

Answers

Answer 1
Answer: The lenght: x
The width: y
x = 3y-5 (cm)
x + y = 150/2 = 75 (cm)
=> 3y-5+y = 75
=> 4y = 80
=> y = 20 (cm)
=> x = 3×20-5 = 55 (cm)

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Find the slope of the following line:
y=2/3x +4

Answers

y = 2/3*x + 4We knowy = mx+ c, m = gradientTherefore, x = 2/3In these questions, the "coefficient" (or multiplier) of x is equal to the gradient.
Slope-intercept form is

y = mx + b

where,
m is the slope
b is the y-intercept

So for the line:
y = 2/3x + 4

2/3 is the slope
4 is the y-intercept

The slope of y = 2/3x + 4 is 2/3

A bathroom is 6 ft 5in long and 4 ft 3in wide what is the area of the bathroom in square feet. I need work with the answer

Answers

you just multiply the sides. 
Firstly, it's easier if you convert both measurements to inches.
so you'd do 6 x 12 = 72 , 72 + 5 = 77 inches
and 4 x 12 = 48 , 48 + 3 = 51 inches.

Then you multiply the sides, so:
77 x 51 = 3927 inches
then you divide by 12 to get how many feet and inches it is
3927/12 = 327 feet and 4 inches

1/x + 1/y = 3/5. What are the denominators x & y

Answers

Answer:

x = 5y over 3y-5

y = 5x over 3x-5

hope this helps

A circle with diameter 11 inches.What is the approximate area of the circle? Use 3.14 for Pi and round the answer to the nearest tenth.
17.3 in2
34.5 in2
95.0 in2
379.9 in2

Answers

Answer:

a=95.0 in^2

Step-by-step explanation:

The area of a circle is:

a=\pir^2

First, we must find the radius

r=d/2

r=11/2

r=5.5

Substitute 5.5 in for r in the formula

a=\pi5.5^2

a=\pi30.25

Substitute 3.14 in for pi  

a=3.14*30.25

a=94.985

Rounded to the nearest tenth:

a=95.0 in^2

Hope this helps! :)

Answer:

95.0 in²

The question and proof is below      

Pls help !!!!!!!!! confused

Answers

If the equation is $5 multiplied by 65 cents, then your answer is $3.25. Cents convert to decimals in math. So, here you go. :)

What is 2x times x squared?

Answers

We want to multiply the monomial 2x by the monomial 2x^2.

Remember that to multiply monomials we need to use the laws of exponents; in this case, the law for multiplying powers with the same base. The rule says that, when you multiply powers of the same base, you just need to add the exponents: (a^m)(a^n)=a^(m+n), (x^2)(x^4)=x^(2+4)=x^6. Also, is worth pointing out that the exponent of a variable with no exponent is 1: x=x^1.

Remember that we also need to multiply their coefficients , which are the numbers that multiply the variables; again, variables with no numbers have a coefficient of 1, so x=1x. Multiply coefficients is easy, you just need to multiply them as you usually do with everyday numbers.

Let's apply all of that to our multiplication:

(2x)(x^2)=(2x^1)(1x^2)=2*1x^(1+2)=2x^3

We can conclude that 2x times x squared is 2x cubed.



2x times x is \boxed{\bf 2x^(3)}.

Further explanation:

A monomial is an expression which contains one term and a monomial includes numbers and variables which are multiplied together. The constant term is multiplies with an another constsnt term and the variable is multiplies with an another variable term.

Law of exponent:

Product with same base: If we multiply the same bases with different exponents then the base remains the same and the exponents are added in the final product.

Calculation:

Now, we are given the two monomials as 2x and x^(2).

Multiplying both the monomials as follows:

\boxed{2x\cdot x^(2)}  

Here, x is a variable and x has power 1 in the first monomial and x has power 2 in the second monomial.

Using the mentioned law of exponents as the variable x is similar in both the monomial and add the powers of both as follows:

\boxed{\begin{aligned}2x\cdot x^(2)&=2x^(1+2)\n&=2x^(3)\end{aligned}}

Therefore, 2x times x is \boxed{\bf 2x^(3)}.

Learn more

1. Problem on the whole numbers are positive integers brainly.com/question/1852063.

2. Problem on the adding and simplifying the numbers brainly.com/question/894273

3. Problem on general form of the equation of the circle brainly.com/question/1506955

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Polynomials

Keywords:  Trinomials, binomials, monomials, polynomials, variables, exponents,  real numbers, degree of polynomials, equations, expressions, coefficients, zero polynomial, constants, integers, function, domain, range, codomain, graph, abscissa, coordinates, roots of polynomials, bivariate polynomials.