Using the formula C = 2πr, find the circumference of a circle with diameter of 28 inches. A. 56 in.
B. 44 in.
C. 28 in.
D. 88 in

Answers

Answer 1

Answer: Diameter = 28 inches

radius, r = Diameter/2 = 28/2 = 14 inches.

C = 2πr

C = 2*π*14

C = 28π

C ≈ 28*3.142

C ≈ 87.976

C ≈ 88 inches

Option D.

Answer 2

Answer: Ok so the given is the length of the diameter.
diameter=28 in
so the radius is half the diameter
radius=28/2=14 in
Circumference formula=2 × pi × radius
C=2(pi)(14) - pi can be considered as 3.14 or the value in the calculator
C=28(PI)
C=87.96 in ≈ 88 in
The easiest way is just use the diameter times the pi
Because 2 times the radius is just the diameter
So we can derive that
C= diameter × pi
C=d(pi)
C=28(pi)
C=87.96 in ≈ 88 in

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What is the simplified base for the function f(x) = 2(3√27(2x)?2
3
9
18

Answers

Answer:

option C is correct i.e. 9

Step-by-step explanation:

We have given that : $f(x)=2 \sqrt[3]{27^(2x)}$

To find : The simplified base of the function f(x)

Solution:

Now, we solve the equation

$f(x)=2 \sqrt[3]{27^(2x)}$

$f(x)=2(27^x)^{(2)/(3)}$

$f(x)=2(3^(2x))$

$f(x)=2((3^2)^(x))$

$f(x)=2(9^(x))$

Therefore, the simplified base of the function f(x) is 9

Answer:

Option C is correct

9 the simplified base for the given function f(x)

Step-by-step explanation:

Using exponent rules:

$(x^m)^n = x^(mn)$

$\sqrt[n]{x^b} = x^{(b)/(n)}$

Given the function:

$f(x) = 2\sqrt[3]{27^(2x)}$

We can write 27 as:

$27 = 3 \cdot 3 \cdot 3 = 3^3$

then;

$f(x) = 2\sqrt[3]{(3^3)^(2x)}$

Apply the exponent rules:

$f(x) = 2\sqrt[3]{3^(6x)}$

Apply the exponent rules:

$f(x) =2 \cdot (3^(6x))^{(1)/(3)} = 2 \cdot 3^(2x)$

⇒ $f(x) = 2 \cdot (3^2)^x = 2 \cdot 9^x$

⇒ $f(x) =2 \cdot 9^x$

On comparing with exponential function $f(x) = ab^x$ where, b is base of the exponent function, then

b = 9

Therefore, the simplified base for the given function is, 9

What is 15/8 as a mixed number

Answers

It would be equal to 1 7/8

1 and 3/4 would be the answer :)

If alexis ate 2/3 of 1/2 of a pie how much did he eat

Answers

She ate 1/3 of the pie

2/3*1/2=2/6=1/3
Alexis ate 1/3 of a pie

The width of a rectangle is 5 feet, and the diagonal is 8 feet. Which is the area of the rectangle? (Round to nearest hundredth.)

Answers

$The \ formula \ for \ the \ area \ of \ a \ rectangle \ is: \n\nA=l\cdot w\n where \ l \ is \ the \ length, \ w \ is \ the \ width \n\n w = 5 \feet , \n diagonal: \ d= 8 \ feet \n \n apply \ the \ Pythagorean \ Theorem:$

$d^2=w^2+l^2 \n \nl^2=d^2-w^2\n\nl^2=8^2-5^2\n\nl^2=64-25\n\nl^2=39$

$l=√(39)\n\nl \approx 6.244998 \ feet\n\nA= 6.244998 * 5= 31.22499\approx 31.23 \ feet^2$

What are the answers to the following.

Answers

Answer:

Step-by-step explanation:

$8-11 =-3\n\nb. -8+10 = 2\n\nc. 13+(-6) = 13-6 \n= 7\n\nd. 7-(-3)\n= 7+3\n=10\n\ne.-5-(-2)\n=-5+2\n=-3\n\nf. -15-(-25)\n=-15+25\n=10\n\ng. -3+(-6)-(-9)\n= -3-6+9\n=-9+0\n=0\n\nh.-20-(-9)-(-8)\n=-20+9+8\n-20+17\n=-3\n\n$

$-2+3-(-4)+(-5)\n-2+3+4-5\n= 1-1\n=0\n\n\nb. 18-(-10)+(-19)-8\n=18+10-19-8\n28-27\n=1\n\nc. 65+(-72)-(-45)\n= 65-72+45\n=-7+45\n=38$

Choose the correct simplification of x to the 3rd power over y to the 5th power all raised to the 2nd power.x to the 5th power over y to the 7th power
x over y to the 3rd power
x to the 6th power over y to the 10th power
x6y10