Michaela catches 3 fish, which weigh a total of 19 1/2 pounds. One fish weighs 7 5/8 pounds and another weighs 5 3/4 pounds. How much does the third fish weigh? Please answer please

Answers

Answer 1
Answer: Steps:

7 5/8 + 5 3/4

7 5/8 + 5 6/8

12 11/8

13 3/8

19 1/2 - 13 3/8

19 4/8 - 13 3/8

6 1/8

ANSWER: 6 1/8


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Make n the subject of the formula t= square root of n+3/n

Answers

Step-by-step explanation:

hi I have answered ur question

Final answer:

To make n the subject of the formula t = square root of n+3/n, we can isolate the square root term by squaring both sides of the equation and rearranging the equation to make n the subject.

Explanation:

To make n the subject of the formula t = √(n+3)/n, we can start by isolating the square root term. To do this, we square both sides of the equation:



t2 = √(n+3)/n2



Next, we can multiply both sides by n2 to get rid of the denominator:



t2n2 = n + 3



Finally, we can rearrange the equation to make n the subject:



n = (t2n2 - 3)/t2

Learn more about Making n the subject of a formula here:

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816mm=_____ cm
Convert 816mm=______ cm

Answers

10 mm = 1 cm 100mm = 10 cm 800 mm = 80 cm 816 mm = 81.6 cm

816mm=81.6 cm. Remember your conversion table (K H D B D C M). Whenever you move right to left on your table, you move your decimal right to left, and vise versa.

Can somebody help on #22 ASAP? Please explain as well! ;)

Answers

to find the answer all you have to do is subtract 130 to 78

Metric unit of length

Answers

centimeters are the metric unit of length
centimeters is your answer
have a great day!

13 points!What is 16,700,000,000,000,000 estimated as the product of a single digit and a power of 10?


A. 2x10^16

B. 2x10^15

C. 1x10^16

D. 1x10^15

Answers

The answer is 1.67x19^16 so in this case it's 2x10^16.

Please help me with this!!!

Answers

Answer:

(f•g)(2)=3 and (g•f)(6)=7

Step-by-step explanation:

look at the tables

where x is equal to both 2 and 7 is where you will find your answer

Hope this helps you!

I agree with the other person ;)