MATHEMATICS HIGH SCHOOL

Which off the following expressions is equal to -3x^2-12A. (-3x+2i)(x-6i)
B. (-3x-6i)(x+2i)
C. (-3x-6i)(x+2i)
D. (-3x-4i)(x-3i)

Answers

Answer 1

Answer:

Answer:

B. (-3x-6i)(x+2i)

C. (-3x-6i)(x+2i)

Since they are the same answer choice. Should be (-3x-6i)(x-2i) should be the correct answer.

Step-by-step explanation:

The polynomial -3x^2-12 can be factored using GCF into -3(x^2+4).

x^2+4 is a sum of squares and factors into the form (x+ai)(x-ai).

x^2+4 factors into (x+2i)(x-2i).

We put them together and have -3(x+2i)(x-2i) = (-3x-6i)(x-2i)

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2x^2+7x-15=0If r and s are two solutions of the equation above and r > s, which of the following is the value of r-s?

1. Find the Least Common Multiple of these two monomials:
See picture

Answers

Answer:

The last choice is correct

$LCM=120a^4b^7c^5$

Step-by-step explanation:

Least Common Multiple (LCM)

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

$12a^4b^2c^5$

$40a^3b^7c^1$

The prime factors of the first monomial are:

$2^2,3,a^4,b^2,c^5$

The prime factors of the second monomial are:

$2^3,5,a^3b^7c^1$

LCM = Multiply $2^3*3*5*a^4*b^7*c^5$

These are all the factors the greatest number of times they occur.

Operating:

$LCM=8*15*a^4*b^7*c^5$

$\boxed{LCM=120a^4b^7c^5}$

The last choice is correct

the difference between two positive integers is 40. one integer is three times as great as the other. find the integer.

Answers

Be the integers: x and y

x - y = 40
x = 3y

Replace x in the first equation:

3y - y = 40
2y = 40
y = 20
x = 60

What is the solution to the equation 4 + 3sqrt 2y = 6

Answers

Answer:

the answer it's not correct because you have to put the 6x

Step-by-step explanation:

if you do not put an x after you put the number it would you would get it wrong

What is the value of p in the equation 10p+2-2p=4p-10
A. 1
B. -1
C. 3
D. -3

Answers

I think the answer is C

The length of a football field is 100 yard and the width is 53 yard. In the fist game of the season, Jos catches the opening kickoff at the corner of the goal line and runs straight as a string the diagonal length of the field to score s touchdown. The next day, the local paper credits Jos for a 100 yard touchdown run, but how far did he actually run

Answers

Given:
Length = 100 yards
Width = 53 yards
Rectangle shape

Jos ran the diagonal length. So, he formed a right triangle. The length Jos ran would be they hypotenuse.

a² + b² = c² ² where c = hypotenuse

100² + 53² = c²
10,000 + 2809 = c²
12809 = c²
c = √12809
c = 113.18 yards.

Find the volume of each figure. Round your answer to the nearest hundredth, if necessary.