MATHEMATICS MIDDLE SCHOOL

Algebra help please?

Answers

Answer 1

Answer:

Answer is 3 seconds

When the bullet reaches the ground, ground being x in graph (and here its s which is = 0)

s = -16t^2 + 48t

s = 0, solve for t

0 = -16t^2 + 48t

0 = t ( -16t + 48)

0 = 16t ( - t + 3)

now you have two equation

0 = 16t and 0 = -t +3 ( you can look at the graph line touches x twice)

0 = 16 t

0 = t ( you know its false, because time = 0)

You are left with

0 = -t + 3

t = 3

It takes 3 seconds for the bullet to return to the ground.

// Hope this helps.

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a rectangle has an area of 30 square meters reminder of 34 meters what are the dimensions of the rectangle

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64 h have any of each other day to

Perimeter of a triangle with side length of 13.9in,10.4,8.5in

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Perimeter =a+b+c

13.9 + 10.4 + 8.5 =

32.8 in (perimeter)

32.8 is the perimeter of that triangle

Please if anyone can help me

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no solution

subtract 7t from both sides

7t - 7t + 3 = 8 + 7t - 7t

3 = 8 is a false statement

Thus the equation has no solution

Does anyone know this?

Answers

Answer:

120 degrees

Step-by-step explanation:

180 - 60 = 120

Answer:

Step-by-step explanation:

all sides are equal to each other:)

How can I get the area of the shaded region?

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Let's work on the triangle first. The x intercept of 2y=27-3x is

0 = 27 - 3x

3x = 27

x = 9

So A(9,0)

B is the meet of 2y=27-3x and y=3x

2y=27-y

3y=27

y=9

y is the height of OAB; we don't really need x

Area(OAB) = $\frac 1 2 (9)(9) = (81)/(2) = 40.5$

Now we have to subtract

$\displaystyle \int_0^9 (3x - x^(\frac 3 2))dx = \frac 3 2 x^2 - \frac 2 5 x^(\frac 5 2) \bigg|_0^9 = \frac 3 2 (9^2) - \frac 2 5 (9^(\frac 5 2)) = (1)/(2)(243) - \frac 2 5 (243) = 24.3$

Area = 40.5 - 24.3 = 16.2

Answer: 16.2

Determine the slope of the line that contains the points (-3, -5) and (0,10)

Answers

the slope is 5
equation is y=5x+10