Jabari owns 100 shares of Stock A and 45 shares of Stock B. For the past month, his stocks have been fluctuating inversely each week. Stock A decreased by m cents per share and Stock B increased by n cents per share. Which equation can be used to find the total change in value of Jabari's shares?
Answers
Stock A = 100
Stock B = 45
For the past months, his stocks inversely decreased.
Stock A = m cents / share
Stock B = n cents * share
So the equation is
= 100 (0.01m) + 45 (0.01n)
= m + 0.45n
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Answers
Note:
Answer:
Answer:
To factor the expression 27x^3 - 1 using the difference of cubes formula, we can follow these steps:
1. Identify the cube root of each term. In this case, the cube root of 27x^3 is 3x, and the cube root of 1 is 1.
2. Write the formula for the difference of cubes, which is: a^3 - b^3 = (a - b)(a^2 + ab + b^2).
3. Replace "a" with 3x and "b" with 1 in the formula.
(3x)^3 - 1^3 = (3x - 1)((3x)^2 + (3x)(1) + 1^2)
4. Simplify the expression inside the parentheses.
(3x - 1)(9x^2 + 3x + 1)
Therefore, using the difference of cubes formula, we can factor 27x^3 - 1 as (3x - 1)(9x^2 + 3x + 1).
Step-by-step explanation:
Answers
Step-by-step explanation:
[tex]18.25 * 40=730[tex]
[tex]18.25 +\frac{1}{2} =18.75[tex]
[tex]18.75*5.25=98.4375[tex]
A: C ∪ D
B: C ∩ D
C: D ⊆ C
D: C ⊆ D
Answers
Answers
Answer:
The large size gives the lowest price per ounce of 3.11875, therefor the best in terms of price
Step-by-step explanation:
Step 1: Determine expression for price per ounce
The expression for the total price of an ice cream dessert is as follows;
T=p×n
where;
T=total price of ice cream
p=price per ounce of ice cream
n=number of ounces of ice cream
Step 2: Convert total price to price per ounce
The expression can be rewritten as;
p=T/n
1. For small 6 ounce at $2.49, T=2.49, n=6-oz
p=2.49/6=0.415
The price per ounce of the small ice cream dessert=$0.415 per ounce
2. For the Medium 10-oz for $3.49, T=$3.49, n=10-oz
p=3.49/10=0.349
The price per ounce of the medium ice cream dessert=$0.349 per ounce
3. For the Large 16-oz for $4.99, T= $4.99, n=16
p=4.99/16=$0.311875
The price per ounce of the medium ice cream dessert=$0.311875 per ounce
4. For the super size 24-oz for $7.69, T=$7.69, n=24
p=7.69/24=0.32
The price per ounce of the super size cup is 0.32 per ounce
The large size gives the lowest price per ounce of 3.11875, therefor the best in terms of price
Answers
Answer:
Jim will incur a loss of $2,400 in the 60-day period under review
Step-by-step explanation:
The question is incomplete. However, one assumption was made in attempting the question, ie, the timeframe was set at 60-days:
Jim likes to day-trade on the internet. On a good day, he averages a $1100 gain. On a bad day, he averages a $900 loss. Suppose that he has good days 25% of the time, bad days 35% of he time, and the rest of the time he breaks even, *what is Jim's balance after a 60-day period* ?
Solution
From the question, given period X = 60 days, and;
Jim's streak is as follows: 0.25X Profit : 0.35X Loss : (100 - (0.25+0.35) Even
Jim's streak = 0.25*60 : 0.35*60 : 0.4*60 = 15 + 21 + 24 (days)
15 profitable days = 15 * $1100 = $16,500
21 bad days 21*$900 = $18,900
24 even days = 24*$0 = $0
Balance after 60 days = $16500+(-$18900)+$0 = $16500-$18900 = -$2400
Final answer:
The expected daily value for Jim's day-trading hobby is -$40, meaning he should expect to lose $40 per day. Over three weeks of trading every weekday, this amounts to a total expected loss of -$600.
Explanation:
The subject of this question is expected value, a concept in probability and statistics, which essentially means the average result of a large number of trials in an experiment. In Jim's case, three possible outcomes are concerning his day-trading hobby: a good day ($1100 gain), a bad day ($900 loss), and a break-even day ($0 gain or loss).
Here's how we calculate:
- A good day: 25% * $1100 = $275
- A bad day: -35% * $900 = -$315
- A break-even day: 40% * $0 = $0
The expected value of one day of trading for Jim is thus: $275 - $315 + $0 = -$40.
If Jim trades every weekday for three weeks (that is, 15 days), we can multiply the daily expected value by 15. So, Jim should expect to lose $40 * 15 = -$600 over three weeks.
Learn more about Expected Value here:
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The complete question is given below:
Jim likes to day-trade on the Internet. On a good day. he averages a $1100 gain. On a bad day, he averages a $900 loss. Suppose that he has good days 25% of the time, bad days 35% of the time, and the rest of the time he breaks even.
a. What is the expected value for one day of Jim's day-trading hobby?
b. If Jim day-trades every weekday for three weeks, how much money should he expect to win or lose?
Answers
2x + 4y = 8
This is a system of equations. You can solve it using elimination. Start by multiplying the top equation by -2.
(x * -2) + (y * -2) = (3 * -2)
-2x - 2y = -6
Now add that and the bottom equation. This will cancel out x.
-2x - 2y = -6
+ 2x + 4y = 8
-----------------------
2y = 2
Solve for y.
2y = 2
y = 2/2
y = 1
Now plug 1 in for y in the first equation.
x + y = 3
x + 1 = 3
Solve for x.
x + 1 = 3
x = 3 - 1
x = 2
So x = 2 and y = 1.