How are mixed numbers used in The real world

Answers

Answer 1

Answer: Often, mixed number are used in terms of amounts of something. You would never say I have 16/5 pies. You would say I have 3 full pies and 1/5 of another pie.

In this example, 3 1/5 is better to use than the improper 16/5

Hope this helps!

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Max was on vacation twice as long is Jared and half as long as Wesley. The boys were on vacation a total of three weeks. How many days with each boy on vacation?

Answers

To begin with, the question is asking for the answer in days, so let's change 3 weeks to days. There are 7 days in 1 week; 3 weeks times 7 days = 21 days.
21 total days of vacation.

Max + Jared + Wesley = 21 days
(Let's use the first letter of their name to represent their vacation time)

M + J + W = 21 [This is the equation we'll be coming back to]

Now, we can use the clues given in the question to have an equation for each variable/boy.

Max was on vacation twice as long as Jared. We can interpret this as M= 2J Max was on vacation only half as long as Wesley. We can interpret this as M = (1/2)W.

So far we have these three equations: M + J + W = 21M = 2J M = (1/2)W

To have an equation for each individual boy, we must rearrange the last two equations in the list.

First, M = 2J.
Divide both sides by 2
M/2 = 2J/2
(1/2)M = J

Second, M = (1/2)W
Multiply both sides by 2
2M = W

New equations:
M + J + W = 21 [From the old list]
J = (1/2)W
W = 2M

Now we can substitute the last two equations into the first one.
M + J + W = 21
M + (1/2)W + 2M = 21
[Combine Like Terms]
(7/2)M = 21

Then, solve for M (Max's vacation days):
Multiply both sides by 2/7
$((2)/(7))* ((7)/(2)m)= ((2)/(7))*(21)$
M = 6

Now we know Max was on vacation for 6 days.

If Max was on vacation twice as long as Jared, that means Jared was on vacation HALF as long as Max.

So...
J = (1/2)M
J = (1/2) * 6
J = 3
Jared was on vacation for 3 days

Wesley was on vacation twice as long as Max so... W = 2M
W= 2*6
W = 12
Wesley was on vacation for 12 days.

Let's double check our answer:
M + J + W = 21 days6 + 3 + 12 = 21
The numbers work out so the math is correct. Hope this helps and makes sense!

Solve the system of equations below by graphing both equations with a pencil and paper. What is the solution?

Answers

Answer: B. (2,1)

Step-by-step explanation:

The given system of equation :

$y=2x-3...........................(1)\n\ny=-2x+5.............................(2)$

Adding equation (1) and (2), we get

$2y=-3+5\n\n\Rightarrow\ 2y=2\n\n\Rightarrow\ y=1$

Substitute the value of y in the first equation , we get

$1=2x-3\n\n\Rightarrow\ 2x=1+3\n\n\Rightarrow\ 2x=4\n\n\Rightarrow\ x=2$

Therefore, the solution to the given system of equations = (2,1)

Answer:

B (2,1)

Step-by-step explanation:

In rectangle $ABCD$, $P$ is a point on $BC$ so that $\angle APD=90^{\circ}$. $TS$ is perpendicular to $BC$ with $BP=PT$, as shown. $PD$ intersects $TS$ at $Q$. Point $R$ is on $CD$ such that $RA$ passes through $Q$. In $\triangle PQA$, $PA=20$, $AQ=25$ and $QP=15$. Find $SD$. (Express your answer as a common fraction.)

Answers

Answer:

$(28)/(3)$

Step-by-step explanation:

Given information: ABCD is a rectangle, $\angle APD=90^(\circ)$ , PA=20, AQ=25 and QP=15.

In a right angled triangle

$hypotenuse^2=base^2+perpendicular^2$

In triangle ABP, AB = 16 and AP = 20. Using Pythagoras theorem we get

$(AB)^2 + (BP)^2 = (AP)^2$

$16^2 + (BP)^2 = 20^2$

$(BP)^2 = 20^2-16^2$

$BP^2 = 144$

$BP = 12$

Since BP = PT, therefore PT = 12.

$AS = BP + PT = 12 + 12 = 24$

AQS is a right angled triangle and AQ = 25. Use Pythagoras theorem in triangle AQS.

$(AS)^2 + (SQ)^2 = (AQ)^2$

$24^2 + (SQ)^2 = 25^2$

$SQ = 7$

Triangle PQT is a right triangle. Use Pythagoras theorem in triangle PQT.

$(PT)^2 + (QT)^2 = (PQ)^2$

$12^2 + (QT)^2 = 15^2$

$QT = 9$

In triangle PTQ and DSQ,

$\angle TQP=\angle SQD$ (Vertical angles)

$\angle PTQ=\angle DSQ$ (Right angles)

Triangle PTQ is similar to triangle DSQ by AA property of similarity.

Corresponding parts of similar triangles are proportional.

$(PT)/(QT)=(SD)/(SQ)$

$(12)/(9)=(SD)/(7)$

On cross multiplication we get

$9SD=12* 7$

$9SD=84$

Divide both sides by 9.

$SD=(84)/(9)$

$SD=(28)/(3)$

Therefore, $SD=(28)/(3)$ .

Help with expanded notation, how do u do this!? Number 15 and 16

Answers

I think that # 15 is 10,000 + 400 + 50 + 6 and #16 is 100,000 + 80,000 + 70 + 5. It's really simple to figure out; just find the number in the place value and, for how many digits after it, substitute zeros (if that makes sense).

Hope this helps!

Answer:

15: 10,000 + 400 + 50 + 8

16: 100,000 + 80,000 + 70 + 5

note: hope i helped, have a great day :)

Step-by-step explanation:

Evaluate.
17 + 330 • 20 ÷ 10² ÷ 2 – 14

Answers

36
you can put it in the calculator ten squared as 10^2

17+330×20÷10^2÷2-14
17+330×20÷100÷2-14
17+330×0.1-14
17+33-14
36

Ending time: 10:08 am elapsed time: 30 minutes

Answers

Answer:

Hence, beginning time is:

9:38 a.m.

Step-by-step explanation:

We know that:

" Elapsed time is the time or difference between a beginning time and an ending time "

Here we are given that the ending time is:

10:08 a.m.

and elapsed time is:

0:30 minutes.

This means the beginning time will be :

ending time - elapsed time.

Hence on counting back 30 minutes from 10:08 am we get the beginning time as:

9:38 a.m.

We have to subtract 30 minutes from 10:08 am, then the elapsed time will be 9 hours 38 minutes.

What is subtraction?

It simply means to deduct something from the object or number of group, place, etc. Subtraction means to take away from the group or a number of objects.

Ending time: 10:08 am elapsed time: 30 minutes. Then the time will be

We know that elapsed means before 10:08 am. So we have to subtract 30 minutes from 10:08 am. Then we have

$\begin{matrix} & 10 & : & 08 \n- & 00 & : & 30 \n& \overline{09} & : & \overline{38}\end{matrix}\n$

Then the time will be 09:38 am.

More about the subtraction link is given below.

brainly.com/question/4319655

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