A small plastic sphere with a charge of -6.0 nC is near another small plastic sphere with a charge of -14 nC . If the spheres repel one another with a force of magnitude 8.3×10−4 N , what is the distance between the spheres?

Answers

Answer 1
Answer: Here is how to answer the question.

Use the formula:
F = kq1q2/r^2 

F = force = 8.3x10^-4N 
q1, q2 = charges 
r = separatioon 
k = constant = 9x10^9 in MKS units 

so we have 

r = sqrt[k q1 q2/F]
r = sqrt[9x10^9*(-14)x10^-9 * (-6)x10^-9 / 8.3x10^-4 ]

r = 0.0302 m

So the distance between spheres is 0.0302 m

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Probably cause 2+2=4 and 4-2=2.

a boeing 747 has a total mass, including passengers and luggage, of 250,000 kg. How much force do the engines supply to achieve a take off velocity of 990 m/s in 35 seconds.

Answers


Acceleration = (change in speed) / (time for the change)

Acceleration = (990 m/s)  /  (35 sec)  =  28.29 m/s²


Force = (mass) x (acceleration)

Force  =  (250,000 kg) x (28.29 m/s²) =  7.07 million Newtons

                                                about  1.59 million pounds .

===========================================

There you have the Physics and the Math.
Does any of this resemble the real world ?
No.  The question is completely bogus.

-- Take-off speed can't be 990 m/s. 
That would be about  2,200 mph, almost 3 times the speed of sound.

-- The take-off run can't accelerate at 28.3 m/s² .
That would be almost 3 G's.  If it didn't rip the wings off of the 747,
it would surely guarantee early use of most of the passengers' barf bags.

-- The Saturn V first-stage booster that sent Apollo to the moon
had a thrust of 7.5 million pounds.  I'm pretty sure that was more
than 4.7 Boeing 747's.
 
================================

Ah hah !  I've just been handed a bulletin, or as they say nowadays,
there is breaking news !

I see that the take-off speed has been revised downward to 90 m/s.
That's right at 200 mph which seems reasonable to me, so let's go
back and do the whole thing again:


Acceleration = (change in speed) / (time for the change)

Acceleration = (90 m/s)  /  (35 sec)  =  2.57 m/s²  (about 0.26 G)


Force = (mass) x (acceleration)

Force  =  (250,000 kg) x (2.57 m/s²) =  643 thousand Newtons

                                               about  144 thousand pounds.

                                                about 1.9% of a Saturn V booster.

I like that a lot better.


PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!The shape of a projectile's trajectory is an ellipse.

True or false?

Answers

The statement is false. The shape of an object's trajectory can be a number of different shapes, not just an ellipse.

A drive find difficulty to drive a car when the ground is cover with ice explain why?

Answers

the ground is less rough, so there is less friction between the ground and the wheels of the car. This makes it unable for the car to move forward

Why are gases good at transferring heat through convection?

Answers

Because gases flow easily.  A hot batch of gas can rise through
the surrounding gas a lot easier than, say, a hot batch of mud can
rise through the surrounding mud.

Answer: The particles can slide past one another.

Explanation : 'The heat energy moves through the material as the particles tin the material move through the material' .

Calculate the maximum acceleration of a car that is heading up a 4º slope (one that makes an angle of 4º with the horizontal) under the following road conditions. Assume that only half the weight of the car is supported by the two drive wheels and that the coefficient of static friction is involved—that is, the tires are not allowed to slip during the acceleration. (Ignore rolling.) (a) On dry concrete.
(b) On wet concrete.
(c) On ice, assuming that μs = 0.100 , the same as for shoes on ice.

Answers

Final answer:

The maximum acceleration of a car moving uphill can be calculated using the formula μs*g*cosθ - g*sinθ where θ is the slope angle, μs is the coefficient of static friction, and g is the acceleration due to gravity. The figures for μs differ depending on the road condition - dry concrete, wet concrete, or ice, substantially affecting the car's acceleration.

Explanation:

The maximum acceleration of a car moving uphill is determined by the force of static friction, which opposes the combined force of the car's weight component down the plane and the force utilized by the driving wheels. The maximum static friction force (F_max) is determined by the coefficient of static friction (μs) multiplied by the normal force (N), which is equivalent to the weight of the car (mg) multiplied by the cosine of the angle (cosθ).

(a) On dry concrete: Since the μs is usually 1.0 on dry concrete and half the weight of the car is supported by the drive wheels, the maximum acceleration can be calculated as μs*g*cosθ - g*sinθ

(b) On wet concrete: The μs is around 0.7 on wet concrete. Substituting this value into the formula would give us the maximum acceleration on a wet surface.

(c) On ice: With a μs value of 0.1 as given, the maximum acceleration on ice can also be calculated using the same formula.

As one can see, the road conditions significantly impact the car's maximum acceleration due to the change in the amount of friction between the tires and road surface.

Learn more about Maximum Car Acceleration here:

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Final answer:

The maximum accelerations for the car going up a 4º slope are 9.3 m/s² on dry concrete, 6.4 m/s² on wet concrete, and -0.1 m/s² on ice.

Explanation:

The maximum acceleration of the car up the slope can be calculated using the equation: a = μs * g * cosθ - g * sinθ, where a is the acceleration, μs is the coefficient of static friction, g is the acceleration due to gravity, and θ is the angle with the horizontal.

To solve this problem, we must teach the student to take several factors into account, including the various coefficients of static friction corresponding to different road conditions, namely dry concrete, wet concrete, and ice.

Considering that each scenario has different values of μs, we fill in the equation with the angles and coefficients of static friction. As a rule of thumb, μs for dry concrete is generally taken as 1.0, for wet concrete as 0.7 and for ice (mentioned in the question) as 0.100.

  1. For dry concrete, a = 1.0 * 9.8 * cos(4) - 9.8 * sin(4) = 9.3 m/s².
  2. For wet concrete, a = 0.7 * 9.8 * cos(4) - 9.8 * sin(4) = 6.4 m/s².
  3. For ice, a = 0.100 * 9.8 * cos(4) - 9.8 * sin(4) = -0.1 m/s².

Learn more about maximum acceleration here:

brainly.com/question/30505958

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