In △ABC, points M and P are points on sides AC and BC respectively. Find the area of △MPC, if BM∩AP=O, AAOM=45 dm2, ABOP=15 dm2, and AAOB=75 dm2. I WILL GIVE YOU BRAINLIEST PLS HELP.
Answers
First calculate the Area of MOP by using congruent altitudes.
(Area MOP)/(Area AOM) = PO/OA = (Area BOP)/(Area AOB)
Area MOP = (Area AOM)*(Area BOP)/(Area AOB) = (45)*(15/75) = 9.
Now, let Area CMP = x. And use two sets of triangles with congruent altitudes.
(Area CMP)/(Area BMP) = x/(9+15) = x/24 = (CP)/(BP).
(Area CAP)/(Area BAP) = (x+54)/90 = (CP)/(BP)
So,
(Area CMP)/(Area BMP) = (Area CAP)/(Area BAP)
or
x/24 = (x+54)/90
90x = 24 (x+54) = 24x + 1296
66x = 1296
x = 19
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9514 1404 393
Answer:
2 and 3
Step-by-step explanation:
Let x and y represent the first and second numbers, respectively.
3x +3y = 15
4x +2y = 14
Dividing the equations by common factors, we can rewrite them to standard form:
x + y = 5
2x + y = 7
Subtracting the first equation from the second gives ...
(2x +y) -(x +y) = (7) -(5)
x = 2
Using either equation to find y, we have also ...
y = 3
The two numbers are 2 and 3.
Answer:
{3m+3n=15
4m+2n=14
Step-by-step explanation:
Answers
The value of the given expression is 63000.
The given expression is (7×9)×10³.
We need to find the value of the given expression.
What is an expression?
An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division.
Now, (7×9)×10³ can be simplified as follows:
63×10³=63×1000
=63000
Therefore, the value of the given expression is 63000.
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brainly.com/question/15034631.
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Answers
Answer:
The statement is false.
Step-by-step explanation:
For any vector 'r' we have
The magnitude is given by
As we know that the upon squaring a term the result is always positive thus the term in right side of equation i is always positive no matter weather the terms (x,y,z) are positive or negative hence we conclude that magnitude of any vectorial quantity is always positive irrespective of it's direction.
Answers
I am assuming you are solving to get a zero, in which case a=2
Answers
The total area of the complete lawn is (100-ft x 200-ft) = 20,000 ft².
One half of the lawn is 10,000 ft². That's the limit that the first man
must be careful not to exceed, lest he blindly mow a couple of blades
more than his partner does, and become the laughing stock of the whole
company when the word gets around. 10,000 ft² ... no mas !
When you think about it ... massage it and roll it around in your
mind's eye, and then soon give up and make yourself a sketch ...
you realize that if he starts along the length of the field, then with
a 2-ft cut, the lengths of the strips he cuts will line up like this:
First lap:
(200 - 0) = 200
(100 - 2) = 98
(200 - 2) = 198
(100 - 4) = 96
Second lap:
(200 - 4) = 196
(100 - 6) = 94
(200 - 6) = 194
(100 - 8) = 92
Third lap:
(200 - 8) = 192
(100 - 10) = 90
(200 - 10) = 190
(100 - 12) = 88
These are the lengths of each strip. They're 2-ft wide, so the area
of each one is (2 x the length).
I expected to be able to see a pattern developing, but my brain cells
are too fatigued and I don't see it. So I'll just keep going for another
lap, then add up all the areas and see how close he is:
Fourth lap:
(200 - 12) = 188
(100 - 14) = 86
(200 - 14) = 186
(100 - 16) = 84
So far, after four laps around the yard, the 16 lengths add up to
2,272-ft, for a total area of 4,544-ft². If I kept this up, I'd need to do
at least four more laps ... probably more, because they're getting smaller
all the time, so each lap contributes less area than the last one did.
Hey ! Maybe that's the key to the approximate pattern !
Each lap around the yard mows a 2-ft strip along the length ... twice ...
and a 2-ft strip along the width ... twice. (Approximately.) So the area
that gets mowed around each lap is (2-ft) x (the perimeter of the rectangle),
(approximately), and then the NEXT lap is a rectangle with 4-ft less length
and 4-ft less width.
So now we have rectangles measuring
(200 x 100), (196 x 96), (192 x 92), (188 x 88), (184 x 84) ... etc.
and the areas of their rectangular strips are
1200-ft², 1168-ft², 1136-ft², 1104-ft², 1072-ft² ... etc.
==> I see that the areas are decreasing by 32-ft² each lap.
So the next few laps are
1040-ft², 1008-ft², 976-ft², 944-ft², 912-ft² ... etc.
How much area do we have now:
After 9 laps, Area = 9,648-ft²
After 10 laps, Area = 10,560-ft².
And there you are ... Somewhere during the 10th lap, he'll need to
stop and call the company surveyor, to come out, measure up, walk
in front of the mower, and put down a yellow chalk-line exactly where
the total becomes 10,000-ft².
There must still be an easier way to do it. For now, however, I'll leave it
there, and go with my answer of: During the 10th lap.
Answers
Answer:
E
Step-by-step explanation:
basically if you do a graph y will start at 5 always because the entrance fee never change. then 0.6 equal 60 cents and since it's per pound you will multiple with x (how many pounds)
Answer:
E.
Step-by-step explanation:
Because it is 0.60 PER pound and an extra $5 so the equation would be C=0.60x+5