MATHEMATICS HIGH SCHOOL

What is the result if you divide –12x8y8 by 3x4y2?a. 4x4y6
b. 4x2y4
c. –4x2y4
d. –4x4y6

Answers

Answer 1
Answer: When dividing two numbers with the same base but with different powers, you subtract the second power from the first and keep the base. So in our case, -12*x^8*y^8 / 3*x^4*y^2 = -4*x^4*y^6. The correct answer is d.
Answer 2
Answer:

Answer:

option d is correct

-4x^4y^6

Step-by-step explanation:

Using exponent rules:

(a^n)/(a^m) = a^(n-m)

Given that:

If you divide -12x^8y^8 by 3x^4y^2

⇒(-12x^8y^8)/(3x^4y^2)

⇒(-4x^8y^8)/(x^4y^2)

Using exponent rules, we have;

⇒-4x^(8-4)y^(8-2)

⇒-4x^4y^6

Therefore, If you divide -12x^8y^8 by 3x^4y^2 we get; -4x^4y^6

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Which of the following is equivalent to 6x 2 + x - 12 ?A. (2x + 3)(3x - 4)
B. (2x - 3)(3x - 4)
C. (2x + 3)(3x + 4)
D. (6x + 3)(x - 12)
E. (x + 3)(2x - 12)
Please show me step by step how to solve this problem
Thanks

Answers

6x^2+x-12=6x^2-9x+8x-12=3x(2x-3)+4(2x-3)\n\n=(2x-3)(3x+4)\n\nother\ method:\n\n6x^2+x-12\na=6;\ b=1;\ c=-12\n\Delta=b^2-4ac\to\Delta=1^2-4\cdot6\cdot(-12)=1+288=289\n\nx_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=√(289)=17

x_1=(-1-17)/(2\cdot6)=(-18)/(12)=-(3)/(2);\ x_2=(-1+17)/(2\cdot6)=(16)/(12)=(4)/(3)\n\n6x^2+x-12=6(x+(3)/(2))(x-(4)/(3))=2\cdot3(x+(3)/(2))(x-(4)/(3))\n\n=2(x+(3)/(2))\cdot3(x-(4)/(3))=(2x+3)(3x-4)

Find the distance between the pair of parallel lines, y = -2x+1 & y = -2x+16.

Answers

Given \ the \ equations \ of \ two \ non-vertical \ parallel \ lines:\n\ny = mx+b_1\ny = mx+b_2\n\nthe \ distance \ between \ them \ can \ be \ expressed \ as : \n\nd= (|b_(1)-b_(2)|)/( √( m^2+1) )

y = -2x+1\ny = -2x+16 \n\n\nd= (|b_(1)-b_(2)|)/( √( m^2+1) ) =(| 1-16|)/( √( (-2)^2+1) ) =(| -15|)/( √( 4+1) ) =(15)/(√(5))\cdot (√(5))/(√(5))=\n \n\n=(15√(5))/(5)=3√(5)\approx 3\cdot 2.24 \approx 6.72

14 Jones downloaded 9 apps onto his tablet in 36 seconds. At this rate, how many apps could hedownload in one minute? (36 seconds=3/5)

Answers