MATHEMATICS MIDDLE SCHOOL

25/7= blank 39/51=blank

Answers

Answer 1

Answer:

25/7 =

7 goes into 25 3 times with 4 left over

25/7 = 3 4/7

39/51 =

divide top and bottom by 3

39/51 =13/17

Answer 2

Answer:

Step-by-step explanation:

25/7 = 3.57142857 ( round to 3.57)

39/51 = 0.76470588 ( round to 0.76)

;)

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Louis wants to place carpet in his rectangular basement. The basement has an area of 864 square feet. The width of the basement is 2/3 it's length. What is the length of Louis's basement?
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Steve and Ed were comparing how much money they earned in a 9 week period. Steve earned $149.53 each week for three weeks. He then earned twice as much each week for the next six weeks. Ed earned $108.77 for two weeks. He then earned three times as much each week for the next seven weeks. How much more did Ed earn than Steve?

Answers

Steve: 149.53 x 3 = 448.59
299.06 x 6= 2242.95
2242.95 + 448.59 =
$2242.59

Ed: 108.77 x 2 = 217.54
326.31 x 7 = 2284.17
2284.17+ 217.54 = $2501.71

$2501.71 - $2242.95 =
$258.76

Ed earned $258.76 more than Steve.

8 friends attend a read a thon. they take turns reading for a total of 3 hours. If each friend reads for the same amount of time, what fraction of an hour does each friend spend reading?

Answers

(3 hours) / (8 friends) = 3/8 hour per friend

Brian flips two coins. How many are in the sample space for flipping two coins?

Answers

Heads: 50%
Tails: 50%
Total: 50 50 chance

The pair of polygons is similar. Find the value of x?

Answers

the answer is d 13 in.

Final answer:

To find the value of x for a pair of similar polygons, set up a proportion comparing the lengths of corresponding sides and solve for x.

Explanation:

The value of x can be found by examining the corresponding sides of similar polygons. For example, if one side of the first polygon is twice as long as the corresponding side of the second polygon, then we can set up the proportion:

Length of side in polygon 1 / Length of side in polygon 2 = 2 / 1

Once we have the proportion set up, we can solve for x by cross-multiplying and then dividing:

Length of side in polygon 1 = 2 * Length of side in polygon 2

So, the value of x is 2 times the length of the corresponding side in the second polygon.

Learn more about similar polygons here:

brainly.com/question/26340868

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a juggler throws a ball into the air, releasing it 5 feet above ground with an initial velocity if 15 fps. she catches the ball in thr other hand 5 feet above the ground. How long was the ball in the air?

Answers

Final answer:

The juggled ball was in the air for roughly 0.94 seconds. Using the principles of projectile motion and gravity, you calculate the time for the ball to rise to its peak and then double this value to get the total time the ball is in the air as it follows the same path back down.

Explanation:

The question is about determining the time a juggled ball stays in the air when thrown up at a particular speed and height. The principles of projectile motion and gravity apply here. The time taken for the ball to rise and fall back to the same height can be found using the physics concept of free fall. While the ball is in the air, it rises and then falls to a final position which is equal to its starting altitude. This is because the ball is thrown and caught at the same height.

From the facts we have, the initial vertical speed is 15 fps (feet per second). Since the acceleration due to gravity is -9.8 m/s² or approximately -32.2 fps² (note that it is negative as it is acting downward), we can use the following equation of motion which is derived from Newton's second law:

final velocity = initial velocity + (acceleration x time)

In this case, the final velocity when the ball reaches the peak of its flight is 0 (since it stops for a moment before falling again), and the acceleration is -32.2 fps². If we rearrange the equation to solve for time (t), we get:

t = (Final velocity - Initial velocity) / acceleration. Substituting the values we get:

t = (0 - 15) / -32.2 = 0.47 s

This is the time taken for the ball to go up. However, the ball takes the same amount of time to come down, so we multiply this by 2 to get the total time the ball is in the air:

Total time = 0.47 x 2 = 0.94 seconds, approximately.

So, the ball was in the air for roughly 0.94 seconds.

Learn more about Projectile Motion here:

brainly.com/question/29545516

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Problems of this sort are frequently found in physics. If you study calculus or physics you'll learn how to create the equation representing the velocity of an object in flight.

Here, you don't need to calculate velocity, but rather time. Start with this equation:

v = v0 + a t^2, where v is the velocity at time t, v0 is the initial velocity, a is the acceleration due to gravity (denoted by g instead of a), and t is the elapsed time.

You are told that v0 is 15 ft/sec. Set v = to 0, as the ball stops moving for the tiniest instant at the top of its trajectory. Use g = - 32 ft (per second squared).

Then 0 = 15 ft/sec - 32 [ft/(seconds squared)] t.

Solve this for t. This is the time required for the ball to come to a complete stop at the top of its trajectory.

Finally, multiply this time by 2, since the ball begins to fall and returns to its original height.

4,083,817 what 3 digits are in the units period?

Answers

The answer is 817.

Further explanation

Problem: given 4,083,817.

Question: what are the 3 digits in the unit period.

This is a problem with place value. Given 4,083,817 which is a large number in the standard form.

The digits in large numbers are in groups of three places, i.e.,

hundreds,
tens,
ones (or units).

The groups are called periods, i.e.,

millions period
thousands period
ones or units period

Commas are typically used to separate the periods.

Let's set the place values from 4,083,817 consecutively as follows.

In the mllions period: 4 ones.
In the thousands period: 0 hundred thousands, 8 ten thousands, 3 one thousands.
In the units period: 8 hundreds 1 tens 7 ones.

Let us say in word form: four million eighty-three thousand eight hundred seventeen.

Hence, three digits in the units period are 817.

Learn more

Explanations and an example of a question about the four types of number form brainly.com/question/4725342
9 ten thousand divided by 10 in unit form brainly.com/question/4786449
Whole numbers are sometimes integers brainly.com/question/1852063

Keywords: the units period, 3 digits, 4,083,817, a large number, standard form, millions, thousands, hundreds, tens, ones, place value, four, eighty-three, seventeen, three, number form

Three digits in the units period are 817.

Given that,

A number is, 4,083,817.

Since, A number 4,083,817 which is a large number in the standard form.

The digits in large numbers are in groups of three places, i.e.,

hundreds,

tens,

ones (or units).

Now, The groups are called periods, i.e.,

millions period

thousands period

ones or units period