What is the surface area, in square inches, of a disco ball with a circumference of 188.5 centimeters?

Answers

Answer 1

Answer: A = 11300 cm2

Hope this helps!

Related Questions

Kim checked 20 markers. 7 of them were working. What percent of here markers were not working?
Dosha is creating a new dessert that has two layers shaped like cones. The inner cone is frozen ice cream and has a diameter of 12 cm and a height of 6 cm. The outer layer is a thin wafer shell, like an upside-down ice cream cone, with a height of 15 cm and the same diameter as the inner layer. Dosha will inject a cream filling into the space.What is the volume of the cream filling? Use 3.14 to approximate pi and express your final answer in hundredths. cm3nvm.. it was 339.12 !
Good luck to:CorStie eer, YGood luck to:CwyShe ee Y ar)34GGood luck to: Cerchie eeラー 5-13-Period:00Date :-sCircles Test1. Identify all tangents for circle O. (1 point) ,2, Define a chord of a circle. (1 pointHFAGOCBDE
if a coin and a number cube are tossed at the same time, what is the probability of tossing heads and rolling an even number
When Ava bought her car, it was worth $19,340. It was expected to decrease at a rate of 12.5% each year.What is best prediction for the value of Ava’s car 10 years after she bought it? (Points : 5)

A local hamburger shop sold a combined total of 574 hamburgers and cheeseburgers on Saturday. There were 74 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Saturday?

Answers

500 hamburgers, I believe.

Which of the following represents the factorization of the polynomial below?
2x2 +11x +5

Answers

Answer:

(2x + 1)(x + 5)

Step-by-step explanation:

2x² + 11x + 5 =

= 2x² + 10x + x + 5

= 2x(x + 5) + (x + 5)

= (2x + 1)(x + 5)

Consider the following two circles. Circle P with center (-1, 2) and radius 3 and circle Q with center (3, 4) radius 5. What sequence of transformations will carry circle P onto circle Q? Select all that apply.A. Dilation centered at Q, followed by reflection across the y-axis
B. Dilation centered at P, followed by reflection across the y-axis and then the line y = -x + 5
C. Translation (x,y) -> (x+4, y+2), followed by dilation centered at Q
D. Dilation (x+y) -> (3/5x, 3/5y), followed by dilation centered at P
E. Reflection over x-axis followed by rotation of 270 degrees

Answers

Answer:

B. Dilation centered at P, followed by reflection across the y-axis and then the line y = -x + 5

Step-by-step explanation:

Circle P.

Centerat (-1, 2).

Radius of 3.

Circle Q.

Center at (3, 4).

Radius of 5.

To carry one circle onto the other, their centers and radius must be the same.

So, circle P must be shifted from (-1, 2) to (3, 4), that means the translation is 4 units to the right side and two units upside, this is the first transformation.

The second transformation must be about stretching the circle P, from a radius of 3 to a radius of 5.

Therefore, the right answer is B.

Answer: Option b and Option c

Kendra is buying bottled water for a class trip.She has 16 bottles left over from the last trip.She buy bottles by case to get a good price.Each case holds 24 bottles.How many cases will she to have to buy if she wants to have a total of 160 bottles of water??.

Answers

She will have to get 6 cases of water.

2. Which is larger?The common ratio, r , in a geometric sequence whose second term is
24 and whose fifth term is 1536
or
The common difference, d , in an arithmetic sequence whose fourth
term is 16 and whose seventh term is 31.

Answers

Answer:

The common difference d is larger than the common ratio r

Step-by-step explanation:

The common difference in the arithmetic sequence $d=u_(n)-u_(n-1)$

The nth term in the arithmetic sequence is $a_(n)=a+(n-1)d$ , where a is the first term

The common ratio in the geometric sequence $r=(u_(n))/(u_(n-1))$

The nth term in the geometric sequence is $a_(n)=a(r)^(n-1)$ , where a is the first term

Geometric sequence

∵ The second term is 24

∴ $u_(2)$ = 24

∵ $u_(2)=a(r)^(2-1)=ar$

- Equate it by its value

∴ ar = 24 ⇒ (1)

∵ The fifth term is 1536

∴ $u_(5)$ = 1536

∵ $u_(5)=a(r)^(5-1)=ar^(4)$

- Equate it by its value

∴ $ar^(4)$ = 1536 ⇒ (2)

Divide (2) by (1)

∴ $(ar^(4))/(ar)=(1536)/(24)$

- Divide up and down by ar

∴ r³ = 64

- Take ∛ for both sides

∴ r = 4

Arithmetic sequence

∵ The fourth term is 16

∴ $u_(4)$ = 16

∵ $u_(4)$ = a + (4 - 1)d

∴ $u_(4)$ = a + 3 d

- Equate it by its value

∴ a + 3d = 16 ⇒ (1)

∵ The seventh term is 31

∴ $u_(7)$ = 31

∵ $u_(7)$ = a + (7 - 1)d

∴ $u_(7)$ = a + 6 d

- Equate it by its value

∴ a + 6 d = 31 ⇒ (2)

Subtract equation (1) from equation (2) to eliminate a and find d

∵ (a - a) + (6 d - 3 d) = (31 - 16)

∴ 3 d = 15

- Divide both sides by 3

∴ d = 5

∵ r = 4 and d = 5

∴ d > r

∴ The common difference d is larger than the common ratio r

Ariel deposited $100 into a bank account. Each friday she will withdraw 10% of the money in the account to spend. Ariel thinks her account will be empty after 10 withdrawls. Do you agree explain.

Answers

Answer: Yes, I agree. $10 will be withdrawn every Friday, resulting in the $100 she deposited being completely gone after 10 withdrawals.

Step-by-step explanation: You will want to find the amount of money being taken from the $100 withdrawal first. Turn the percent into a decimal, which should result to 0.10. Take this decimal and multiply it with 100 to get the amount of money being taken out of the account each week, which should be $10. I would go about answering this by multiplying the $10 by the amount of 10 withdrawals. This would result in 100. This answers the question because we are trying to see if 10 withdrawals will completely deplete the $100 in the account.

Other Questions

I have two-thirds of a square and I want to divide it by one-half. How many pieces would I have?

8y-10=-3y+2 what does that equal?

How to evaluate this function F(x+5) using this expression:F(x)=3x-4

Factorise this72-6x