What type of reaction occurs between Mg and HCl and explain why?

Answer:

engineering

Explanation:

when you think about the advancements in engineering over the years vs the advancements in science, engineering fits the "fast, better, cheaper" a lot more. Cars, for example, are engineered and over the years cars have been getting faster, more reliable/safe, and more affordable.

Science can also be focused on being better/more reliable/efficient, but this is mainly for things like medicine, and not science as a whole. How can "faster, better, cheaper" apply to a biologist, who studies nature?

Answer:

The mass number of an isotope is the sum of neutrons and protons.

Explanation:

In any elemental isotope, the only things that will affect molar mass and mass number is the number of protons and neutrons. Electrons are not counted because we usually assume they are equal to the amount of protons and have no weight.

Protons are what gives the element its atomic number and the neutrons determine the type of isotope it is within the element.

For instance:

There can be a regular Carbon - 12

But there are isotopes like Carbon - 13 and Carbon - 14.

*The number of protons stays the same but the number of neutrons are different

Answer: 9.13g NO

Explanation:

First, I list what I know, which is the values of STP, the volume, the constant R, and the molar mass of NO; I also include what I'm looking for, which is n, the number of moles of NO.

STP = 273.15K, 1 atm

P = 1 atm

V = 6.82L

R = 0.0821 L*atm/mol*K

T = 273.15K

n = ?

NO mass: 30.01 g/mol

Then, I use the ideal gas law, PV = nRT, to find the number of moles of NO:

(1 atm)(6.82 L) = n()(273.15K)
(1 atm)(6.82 L) = n()
(1 atm)(6.82 L) / () = n       => divided both sides by 22.4L*atm/mol
n = 0.304 mol NO

Then, I use the molar mass of NO, 30.01 g/mol, to convert from mol NO to g NO:

g NO = 0.304 mol NO()
         = 9.13 g NO

I hope this helps! :)

Answer:

Desk

Water

Cloud

Helium

Explanation:

To solve this we use the equation,

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

65 x V1 = 2 x 200 L

V1 = 6.15 L