drew purchased 3 books each with a different price, for $24. The cost of each book was multiple of 4. what could be the prices of the 3 books?
Answers
The cost of three books are $4, $8 and $12.
What is linear equation in one variable?
The linear equations in one variable is an equation which is expressed in the form of ax + b = 0, where a and b are two integers, and x is a variable and has only one solution.
According to the given question
We have
Number of books purchased by Drew = 3
Total cost of the three books = $24
Cost of each book is multiple of 4.
Let the cost of three books be 4x, 8x and 12x.
So, we have
A linear equation in one variable
4x + 8x + 12x = 24
⇒ 24 x = 24
⇒ x = 1
Therefore, the cost of three books will be
4x = 4 × 1 = $4
8x = 8 × 1 = $8
12x = 12 × 1 = $12
Learn more about the linear equation in one variable here:
#SPJ2
Related Questions
Find the equation of the line that passes through (3, 1) and has a y-intercept of –2.What would be the slope of the line?
A recipe needs 4 cups of milk and 6 cups of grated cheese. what is the ratio of the number of cups of grated cheese in the recipe? A. 2:3 B. 2:5 C. 6:4 D. 4:10
Complete the solution the equation. Find the value of y when x equals 15 .
You have an initial amount of $45 in a savings account and you deposit an equal amount into the account each week. After 5 weeks the account holds $105. Write an equation that represents the amount yy (in dollars) of money in the account after xx weeks
Answers
Answer:
YX = 22
Step-by-step explanation:
Similar triangles. So,
Cross multiplication
45*(x+8) = 30 * (3x - 9)
45x + 360 = 90x - 270
360 = 90x - 270 - 45x
360 = 45x - 270
360 + 270 = 45x
45x = 630
x = 630/45
x = 14
YX = x +8 = 14 + 8 = 22
Answers
Answer:
Step-by-step explanation:
hello :
F(x)= squareroot(x)
x=1 : F(1)= squareroot(1) = 1
x=9 : F(9)= squareroot(9) = 3
Answers
Distribute the 8 to everything in parentheses.
8x-8*9
That is your answer using distributive property.
Have a good day and don't forget to mark me as Brainliest!!! XD
Answers
Answers
Start by holding the first letter:
E - XAM
E - XMA
E - MAX
E - MXA
E - AXM
E - AMX
So there are 6 combinations here.
Repeat for all 4 letters.
6 x 4 = 24
This is same as 4x3x2x1.
For 3 unique characters, it is 3x2x1.
For 5 unique characters, it is 5x4x3x2x1
And so on...
Answers
4 out of the 12 cups are decaf, so the odds of selecting a decaf cup by random is 4/12 or 1/3
Alternatively 8 of the 12 cups are caffeinated, so the odds of selecting a caffeinated cup by random is 8/12 or 2/3
P(decaf)=1/3
P(caf)=2/3
But those odds are only for the first cup picked. The second cup has 4 probabilities...
1. Picking a decaf cup for the second time
2. Picking a decaf cup for the first time
3. Picking a caf cup for the second time
4. Picking a caf cup for the first time
So lets find the probability of each event...
1. Picking a decaf cup for the second time. If a decaf cup has already been picked, then the odds of drawing another one is 3/11
2. Picking a decaf cup for the first time. If a decaf cup hasn't already been picked, then the odds of drawing one is 4/11
3. Picking a caf cup for the second time. If a caf cup has already been picked, then the odds of drawing one is 7/11
4. Picking a caf cup for the first time. If a car cup hasn't already been picked, then the odds of drawing one is 8/11.
Okay, so now we can solve for the various possibilities.
1. Picking a decaf cup for the second time
1/3*3/11=3/33
2. Picking a decaf cup for the first time
2/3*4/11=8/33
3. Picking a caf cup for the second time
2/3*7/11=14/33
4. Picking a caf cup for the first time
2/3*8/11=16/33
Both cups were caffeinated, so neither were decaf.
Answer= Neither cup is decaf.