4 hours and 39 minutes before 7:53 p.m. is 6:34 p.m.
To find the time 4 hours and 39 minutes before 7:53 p.m., we can subtract the given time from the duration.
Step 1: Convert 4 hours and 39 minutes into minutes.
4 hours = 4 * 60 = 240 minutes
Total duration = 240 minutes + 39 minutes = 279 minutes
Step 2: Subtract the duration from the original time.
7:53 p.m. - 279 minutes
Subtract the minutes first:
53 minutes - 279 minutes = -226 minutes
Now, since the result is negative, we need to "borrow" an hour from the original time:
7 p.m. - 1 hour = 6 p.m.
So, 4 hours and 39 minutes before 7:53 p.m. is 6:34 p.m.
To know more about hours:
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3 arrays - 1 x 9 (or 9 x 1) and 3 x 3
Hence, the number of arrays = 2 x 2 = 4 = even
First, we pair the different factors of 9.
The different factors of 9 are:
(1, 9) and (3, 3)
For each pair, Mr. Deets can make 2 arrays.
So, the total number of arrays that Mr. Deets can make = 2 x 2 = 4 and hence the number of arrays is even.
Answer:
4 arrays,
Number of arrays is even.
Step-by-step explanation:
∵ The possible pairs of two numbers which give 9 after multiplication,
( 3, 3) and (9, 1),
So, the possible array would be,
3 × 3, 9 × 1
Note : 9 × 1 can also be written as 1 × 9,
According to the question,
For each pair of different factors, there are two arrays,
3 × 3 and 9 × 1 are two arrays with no same factor,
Hence, the total arrays = 2 × 2 = 4
Which is an even number.
Answer:
Refer below for the explanation.
Step-by-step explanation:
As per the question we are asked to combine f(n) = 11 and g(n) = −2(n − 1), both of them to create arithmetic sequence and solve for 31st term.
So first we are about to solve and combine both of the equation which becomes ,
Fn = 11 -2(n-1)
Fn=11-2(n-1)
F31=-49
Fn=11-2(n-1)
F31=-51
Fn=11+2(n-1)
F31=71
Fn=11+2(n-1)
F31=73
To create an arithmetic sequence using the given functions, we add the functions together and substitute the desired term. The 31st term of the arithmetic sequence is -49.
To combine the functions f(n) = 11 and g(n) = -2(n - 1) into an arithmetic sequence, we need to find the common difference between the terms. The common difference between the terms in an arithmetic sequence is obtained by subtracting one term from the previous term. In this case, the common difference is g(n). So, the arithmetic sequence can be expressed as an = f(n) + g(n).
For the 31st term, we substitute n = 31 into the equation and calculate:
a31 = f(31) + g(31)
a31 = 11 + [-2(31 - 1)]
a31 = 11 + [-2(30)]
a31 = 11 + [-60]
a31 = -49
Therefore, the 31st term of the arithmetic sequence an is -49.
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Final value: 60
(A) 70% (B) 500% (C) 50% (D) 600%