Four different sets of objects contain 2, 5, 6, and 7 objects, respectively. How many unique combinations can be formed by picking one object from each set?

Answers

Answer 1

Answer: The correct answer for the question that is being presented above is this one: "A. 960."Four different sets of objects contain 2, 5, 6, and 7 objects, respectively.

= 2 * 5 * 6 * 7
= 960

Here are the following choices:
A. 960
B. 141
C. 23
D. 529

Answer 2

Answer:

Answer: 420

Step-by-step explanation:

2*5*6*7 = 420

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Which unit of measurement would be the most appropriate to measure how much water is in a lake?A : Liter

B : Kiloliter

C : Gram

D : Kilometer

Answers

B would be most appropriate to measure a large volume of water such as in a lake- KILOLITER

Kiloliter since the volume of water is large.

Grams and kilometer are for mass and distance respectively

what is 8 divided by 2 with 2+2 inn the parenthesis. I want to befriend the first person to get it. It's hard but have fun!!!

Answers

Answer:

16 or 1. There are 2 different answers depending on how you take the question as.

Step-by-step explanation:

8÷2(2+2)=

8÷2(4)=

4(4)=

8÷2(2+2)=

8÷2(4)=

8÷8=

How do I differentiate (200000ln(t-0.1))/(39.95t^2)

Answers

$f(x)=(200000\ln(t-0.1))/(39.95t^2)=(4000000)/(799)\cdot(\ln(t-0.1))/(t^2)\nf'(x)=(4000000)/(799)\cdot((1)/(t-0.1)\cdot t^2-\ln(t-0.1)\cdot2t)/(t^4)\nf'(x)=(4000000)/(799)\cdot((t)/(t-0.1)-2\ln(t-0.1))/(t^3)\nf'(x)=(4000000\left((t)/(t-0.1)-2\ln(t-0.1)\right))/(799t^3)$

Answer:

$\frac { dy }{ dt } =\frac { 8\cdot { 10 }^( 6 ) }{ 799{ t }^( 2 ) } \left\{ \frac { 5 }{ 10t-1 } -\frac { \ln { \left( t-\frac { 1 }{ 10 } \right) } }{ t } \right\}$

Workings below. Don't know if it could've have been simplified further.

I've made a "smooth criminal" version, just in case you like things compressed.

$\frac { dy }{ dt } =\frac { n }{ { t }^( 2 ) } \left\{ \frac { 1 }{ t-k } -\frac { \ln { \left( { \left( t-k \right) }^( 2 ) \right) } }{ t } \right\} \n \n n=\frac { 4\cdot { 10 }^( 6 ) }{ 799 } ,\quad k=\frac { 1 }{ 10 }$

A man wishes to cover his ﬂoor with tiles, each one measuring 3/4 inch by 2 inches. If his room is a rectangle, measuring 12 feet by 18
feet, how many such tiles will he need?

A) 144, B) 1152, C) 1728, D) 9216, E) 20736

Plz help me with this problem.. :-(

Answers

The number of tiles required to completely cover the floor is A) 144.

What are the area and perimeter of a rectangle?

We know the perimeter of any 2D figure is the sum of the lengths of all the sides except the circle and the area of a rectangle is the product of its length and width.

We know the area of a rectangle is (length×width).

Given, His room is a rectangle, measuring 12 feet by 18 feet,

Therefore, The area of the room is

= (12×18) sq feet.

= 216 sq feet.

Also given one measures 3/4 inches by 2 inches.

Therefore the area of one tile is,

= [3/4×(2)] sq inches.

= 3/2 sq inches.

So, The number of tiles requires is the area of the room divided by the area of one tile which is,

= (216/(3/2)).

= 216×(2/3).