Given: Length of rod (L) = 80 cm
Weight of rod (W) =2.0 N
From the attached pictorial diagram,
XY = 80 cm,,XC = 40 cm, XA = 20 cm, AC = 20 cm
Let AB = z cm
Apply the principle of moment about the thread,
5.0 N × AX = (6.0 N × AB) + (2.0 N ×AC)
or, 5.0 N × 20 cm = (6.0 N × z cm) + (2.0 N ×20 cm)
or. AB = z = 10 cm
Now, distance XB = XA + AB = 20 cm + 10 cm = 30 cm
Hence, 6.0 N weight should be suspended from X end at distance of 30 cm
6.0 N weight must be placed 0.30 meters (or 30 cm) from end X to keep the rod in equilibrium.
To find the distance of the 6.0 N weight from end X that will keep the rod in equilibrium, you can use the principle of moments (also known as the law of torques). In equilibrium, the sum of the clockwise moments (torques) must be equal to the sum of the counterclockwise moments (torques).
Let's consider the moments (torques) about the point where the rod is suspended:
The 2.0 N weight (the rod's weight) is acting at the midpoint of the rod, which is 40 cm from the suspension point. The moment due to this weight is 2.0 N * 0.40 m = 0.80 N·m in the counterclockwise direction.
The 5.0 N weight at end X is acting at a distance of 20 cm (0.20 m) from the suspension point. The moment due to this weight is 5.0 N * 0.20 m = 1.00 N·m in the counterclockwise direction.
The 6.0 N weight hanging on the rod at an unknown distance "d" from end X creates a moment in the clockwise direction. So, the moment due to this weight is 6.0 N * d m in the clockwise direction.
In equilibrium, the sum of the counterclockwise moments must equal the sum of the clockwise moments:
0.80 N·m + 1.00 N·m = 6.0 N * d m
Now, solve for "d":
1.80 N·m = 6.0 N * d m
Divide both sides by 6.0 N:
d m = 1.80 N·m / 6.0 N = 0.30 m
So, the 6.0 N weight must be placed 0.30 meters (or 30 cm) from end X to keep the rod in equilibrium.
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Answer:
c
Explanation:
c
Answer:
B. have a good day :)
Answer:
the mass of two objects and the distance between two objects
Explanation:
The gravitational force between two objects depends on their masses and the distance between them. The two objects in the universe with the greatest gravitational force acting between them are the Earth and Sun due to the Sun's mass and the relatively short distance between Earth and the Sun.
The gravitational force between two objects depends on two major factors according to the universal law of gravitation: the masses of the two objects and the distance between them. In essence, the greater the mass of the objects, the greater the gravitational force between them; and the closer the objects are to each other, the stronger this force will be.
Considering these factors, the two objects in the universe that have the greatest gravitational force acting between them are the Earth and the Sun. The Sun is the most massive object in our solar system and the Earth, though not the largest, is relatively close to the Sun compared to most other objects in space.
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owl
plant
snake
cricket
Answer:
snake
Explanation:
B. pulley
C. wedgd
D. inclined plane
The inclined plane is the best simple machine to assist with moving heavy objects into a truck. It allows for less force to be used by distributing the required force over a longer distance.
The simple machine that is best suited to assist with the task of moving heavy objects into a moving truck 1.5 meters above the ground is the inclined plane (option D).
An inclined plane is a flat surface that is inclined or sloped, which allows us to move objects up or down with less force. By using an inclined plane such as a ramp, we can reduce the amount of force needed to lift the heavy objects into the truck.
For example, instead of trying to lift a heavy object straight up into the truck, which would require a significant amount of force, we can use an inclined plane to gradually raise the object by pushing it up the inclined surface. This allows us to distribute the required force over a longer distance, making it easier to move the object.
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