Answer: 154.09 g
Explanation:
3 Mg + 2 FeCl3 = 3 MgCl2 + 2 Fe
The mass of MgCl2 produced is calculated:
m MgCl2 = 175 g FeCl3 * (1 mol FeCl3 / 162.2 g) * (3 mol MgCl2 / 2 mol FeCl3) * (95.21 g MgCl2 / 1 mol) = 154.09 g
a. Metallic
b. Ionic
c. Nonpolar covalent
d. Polar covalent
The Gibbs free energy change for this reaction at 298 K is approximately -54,484.8 J.
Calculating the Gibbs free energy change (ΔG) for a reaction at a given temperature using the Gibbs-Helmholtz equation,
ΔG = ΔH - TΔS
ΔG = (-144,600 J) - (298 K)(-301.2 J/K)
ΔG = -144,600 J + 90,115.2 J
ΔG = -54,484.8 J
ΔG = -54,484.8 J
Converting to kilojoules:
ΔG = -54,484.8 J / 1,000
= -54.48 kJ
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(2) the beaker to the air
(3) the water to the ice cubes
(4) the water to the beaker