Given:
P1 = 400 kPa
T1 = 110 K
T2 = 235K
Required:
P2
Solution:
Apply Gay-Lussac’s law where P/T = constant
P1/T1 = P2/T2
P2 = T2P1/T1
P2 = (235K)(400kPa) / (110K)
P2 = 855 kPa
B. Under the zone of saturation
C. In the layer of bedrock
D. At the top of the zone of saturation
B. Energy as heat flows from a higher temperature to a lower temperature
C. The amount of het in a closed system is constant
D. Energy as heat flowing into an object is determined by the amount of work done on the object.
I know the answer is not C.
b. variable
c. control
d. hypothesis