in 1994, Vladimir Kurlivich , from Belarus, set the world record as the world's strongest weight lifter. he did this by lifting and holding above his head a barbell whise mass was 253kg. Kurlovich's mass at the time was 133 kg. caculate the normal force exerted on each of his feet during the time he. was having ldi g the barbell

Answers

Answer 1
Answer:

The free-body diagram of your question is; 2 downward forces (253 kg mass of barbell & 133 kg body mass of Kurlovich) acting together on a point supported by 2 upward forces as normal forces exerted by Kurlovich's feet.  

Solving the normal forces exerted by 2 feet :  

Summation of Forces Vertical = 0  

2 Dowwnard Forces = 2 Upward Forces (2F)  

253 + 133 = 2F  

2F = 386 Kgs  

F = 386 / 2  

F = 193 Kgs (Normal Force Exerted by Each Foot)

Answer 2
Answer:

Final answer:

To calculate the normal force exerted on each of Vladimir Kurlovich's feet while lifting the barbell, we need to consider the weights of Kurlovich and the barbell. The normal force is equal to the sum of the two weights.

Explanation:

To calculate the normal force exerted on each of Vladimir Kurlovich's feet while lifting the barbell, we need to consider the weight of Kurlovich and the weight of the barbell. The normal force is equal to the sum of Kurlovich's weight and the weight of the barbell, as it balances the gravitational force pulling them downwards. Kurlovich's weight can be calculated using his mass and the acceleration due to gravity, which is approximately 9.8 m/s².



Step 1:


Calculate Kurlovich's weight:
Mass = 133 kg
Acceleration due to gravity = 9.8 m/s²
Weight = Mass × Acceleration due to gravity
Weight = 133 kg × 9.8 m/s²

Step 2:


Calculate the weight of the barbell:
Mass = 253 kg
Acceleration due to gravity = 9.8 m/s²
Weight = Mass × Acceleration due to gravity
Weight = 253 kg × 9.8 m/s²

Step 3:


Calculate the normal force exerted on each foot:
Normal force = Kurlovich's weight + Barbell's weight

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